Work and Energy Problems [help]

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Homework Help Overview

The discussion revolves around work and energy problems, specifically focusing on calculating the work required to accelerate an electron and to stop a car. The subject area includes concepts of kinetic energy and work-energy principles.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate work for two different scenarios involving an electron and a car. Some participants question whether the second question provides sufficient information, while others suggest that work is related to the change in kinetic energy.

Discussion Status

Participants are exploring the calculations for kinetic energy and how they relate to the work needed to stop the car. There is some guidance provided regarding the approach to both problems, but no consensus has been reached on the first question about the electron.

Contextual Notes

There is a mention of the need to check unit conversions and significant figures in the calculations, indicating that precision in these areas is under consideration.

krypt0nite
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1) How much work does it take to accelerate an electron(mass=9.11x10^-31kg)
from rest to a speed of 5.0x10^6 ms?

I know you have to use more than 1 equation to solve it but I can't seem to get close to an answer.

2) How much work must be done to stop a 1000-kg car traveling at 100km/h?

Is it me or does this question not have enough info.
 
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krypt0nite said:
Is it me or does this question not have enough info.
It's you. :smile: Remember that work done on an object equals its change in KE.
 
krypt0nite said:
2) How much work must be done to stop a 1000-kg car traveling at 100km/h?

KE = 1/2mv^2
KE = 1/2(1000)(27.278)^2
KE = 385809 Joules
So the work to stop it would be that much?
 
And I assume the 1st question is done the same way?
 
krypt0nite said:
KE = 1/2mv^2
KE = 1/2(1000)(27.278)^2
KE = 385809 Joules
So the work to stop it would be that much?
That's the idea. (Check your conversion of 100km/hour.) (Don't state so many significant figures in your answer.)

And, yes, the first problem is the same idea.
 
Doc Al said:
That's the idea. (Check your conversion of 100km/hour.) (Don't state so many significant figures in your answer.)

And, yes, the first problem is the same idea.
Thanks SOO MUCH!
 

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