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Bertrand's Box Paradox and Monty Hall Problem 
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#1
Sep2708, 12:47 PM

P: 224

This thing is making me pull my hair out: http://en.wikipedia.org/wiki/Bertrand%27s_box_paradox Can someone give me a good explanation of this?
As for the Monty Hall Problem, I think I understand it. This is how I think of it: There is a 1/3 possibilty of picking the correct door and 2/3 possibility of picking the wrong door. And after one of the empty doors has been revealed, then by switching your choice, that 2/3 possibility of picking the wrong door becomes a 2/3 possibility of picking the correct door.  Is this a legitimate way of understanding it? 


#2
Sep2708, 02:06 PM

P: 364




#3
Oct608, 03:21 PM

P: 31

Monty Hall Problem: itīs easy to understand it with 10 doors. There is a 1/10 possibilty of picking the correct door and 9/10 possibility of picking the wrong door. You make your choice. And after 8 of the empty doors has been revealed, you choice still 1/10 possibilty of picking the correct door and the other closed door is 9/10 possibility of picking the correct door.



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