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Molarity and Oxidation states

 
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Oct27-08, 05:32 PM   #1
 

Molarity and Oxidation states


1. The problem statement, all variables and given/known data

I wasn't sure about some of these problems, am I doing them correctly?

1) What volume of each of the following bases will react completely with 25.00 mL of 0.200 M of HCl?

a) 0.100 M NaOH

.02500 L x .200 mol HCl/1 L = .00500 mol HCl

.100 M NaOH = .00500 mol NaOH/v ~ v = .0500 L NaOH

b) 0.0500 M Ba(OH)2

.0500 M Ba(OH)2 = .00500 mol HCl/v ~ v = .100 L Ba(OH)2

c) .250 M KOH = .00500 mol KOH/v ~ v = .0200 L KOH

2) Assign oxidation states for all atoms in each of the following compounds:

a) KMnO4
K: -1
O: -2
Mn: +7


b) Hg2Cl2
Hg: +1
Cl: -1


c) NaBiO3
Na: +1
Bi: +5
O: -2


d) CO
C: +2
O: -2


e) Ca(NO3)2
Ca: +2
N: +5
O: -2


f) HAsO2
H: +1
As: +3
O: -2


3) Specify which of the following are redox reactions, and identify the oxidizing agent, the reducing agent, the substance being oxidized, and the substance being reduced.

a) HCl (g) + NH3 (g) --> NH4Cl (s)

-- not a redox reaction

b) Cu (s) + 2Ag+ (aq) --> 2Ag (s) + Cu2+ (aq)

Oxidized: Cu

oxidizing agent: Ag+

Reduced: Ag+

Reducing agent: Cu
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Oct27-08, 05:55 PM   #2
 
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Quote by Quincy View Post
b) 0.0500 M Ba(OH)2

.0500 M Ba(OH)2 = .00500 mol HCl/v ~ v = .100 L Ba(OH)2
In what molar ratio do they react?

K: -1
O: -2
Mn: +7
Alkali metals in compounds have always the same ON, and it is not -1.
Oct27-08, 06:38 PM   #3
 
Quote by Borek View Post
In what molar ratio do they react?
2HCl + Ba(OH)2 --> BaCl2 + 2H2O

HCl and Ba(OH)2 react in a 2:1 ratio, I realized that after I posted the thread; so the volume of Ba(OH)2 is 0.0500 L?



Quote by Borek View Post
Alkali metals in compounds have always the same ON, and it is not -1.
That was a typo, I meant to say K: +1.
Oct27-08, 06:45 PM   #4
 
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Molarity and Oxidation states


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