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uniform continuity |
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| Nov18-08, 10:25 PM | #1 |
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uniform continuity
1. The problem statement, all variables and given/known data
suppose f and g are uniformly continuous functions on X and f and g are bounded on X, show f*g is uniformly continuous. 3. The attempt at a solution I know that if they are not bounded then they may not be uniformly continuous. ie x^2 and also if only one is bounded they are not necessarily uniformly continuous. not sure what to do if they are both bounded |
| Nov19-08, 06:04 AM | #2 |
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| Nov19-08, 08:13 AM | #3 |
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uniform continuity is intuitively a bit like saying the function doesn't have an infinite slope anywhere...
And if they are both bounded, is their product too bounded? |
| Nov19-08, 09:48 AM | #4 |
Recognitions:
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uniform continuity
Get your epsilons and deltas out. You want to show |f(x)g(x)-f(y)g(y)| can be made uniformly small if |x-y| is small. Hint: |f(x)g(x)-f(y)g(y)|=|f(x)g(x)-f(x)g(y)+f(x)g(y)-f(y)g(y)|. |f(x)-f(y)| and |g(x)-g(y)| can be made small since they are uniformly continuous. Do you see why f and g need to be bounded? Use epsilons and deltas to make the meaning of 'small' precise.
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