
#1
Dec108, 06:53 PM

P: 12

1. The problem statement, all variables and given/known data
A 9.00kg hanging object is connected, by a light, inextensible cord over a light, frictionless pulley, to a 5.00kg block that is sliding on a flat table. Taking the coefficient of kinetic friction as .200, find the tension in the string 2. Relevant equations F = ma 3. The attempt at a solution Fk = ma a = (9.8 N friction force)/(5.00 kg) = 1.96 which is approximately 2 ΣFx= T  Fk = ma T = Fk + ma T = (9.8N) + total mass 14N(1.96 m/s^2) T = 37.24 or if you use 2 for the acceleration you get 37.8 which is the right answer Did I do this right? Please help me to understand why. 



#2
Dec108, 07:33 PM

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P: 5,959




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