|Dec16-08, 01:22 AM||#1|
Electric Field Intensity
1. The problem statement, all variables and given/known data
Find Enet (magnitude and direction) at point A and include a vector diagram.
q1 = 2.0x10^-6 C
q2 = 6.0x10^-6 C
r1 = 2.5x10^-3 m
r2 = 1.7x10^-3 m
2. Relevant equations
E = Klql/r^2 or E = Kq/r^2 (the first equation just has absolute values around the q for reminder but they both are the same thing)
3. The attempt at a solution
First I looked at the diagram and I know that the electric field created by a charge will always put away from a positive charge and towards a negative so I drew a vector diagram for that at point "A" using tip to tail method, then I joined E1(electric field created by q1) and E2(electric field created by q2) to have a resultant of E.
I then used the equation E = kq/r^2 to find out what E1 and E2 are and I found out that they equal 2.8x10^9 and 1.9x10^10 respectively. My question, now I have to use the component method of vector addition to find out what E is but I need an angle to do that. Is the angle in this case 90 degrees?
|Dec16-08, 07:44 AM||#2|
|Dec16-08, 04:05 PM||#3|
Then I took those numbers and I directly plugged it into the equation E= kq/r^2.
|Similar Threads for: Electric Field Intensity|
|Net Electric Field Intensity please help||Introductory Physics Homework||14|
|Intensity of Electric field||Advanced Physics Homework||4|
|E&M - Electric Field Intensity in Microwave||Advanced Physics Homework||0|
|Electric Field Intensity||Introductory Physics Homework||1|
|Electric Field Intensity||Introductory Physics Homework||2|