Question about momentum involving shooting a hockey puck

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SUMMARY

To determine how fast a hockey player must shoot a puck to force a goalie backwards by 5 feet, one must consider the coefficient of friction between the ice and the goalie's skates, using the work-energy principle: W = Fd = (uN)d = (umg)d. Additionally, the kinetic energy equation K = 1/2mv² can be utilized to calculate the necessary velocity. The impact of the puck on the goalie will also generate torque about the goalie's center of mass, which is crucial for understanding the dynamics involved in this scenario.

PREREQUISITES
  • Understanding of basic physics principles, including work-energy and kinetic energy equations.
  • Knowledge of friction coefficients, particularly in the context of ice and skates.
  • Familiarity with torque and its effects on motion.
  • Basic concepts of momentum and force dynamics in sports physics.
NEXT STEPS
  • Research the coefficient of friction for ice and hockey skates to apply in calculations.
  • Learn about the relationship between torque and angular motion in sports contexts.
  • Explore advanced physics simulations to model puck impact scenarios.
  • Investigate real-world examples of puck speeds and goalie reactions in professional hockey.
USEFUL FOR

This discussion is beneficial for physics students, sports scientists, hockey coaches, and players interested in the mechanics of puck dynamics and goalie interactions.

meeklobraca
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This is not homework, just a curious question.

What would need to be figured out, to determine how fast a hockey player would have to shoot the puck at a goalie, for the goalie to be forced backwards about 5 feet. The idea was being floated about if a player could shoot a puck so fast that the puck and the goalie would go into the net effectivly being a goal.
 
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Interesting question. I imagine that you are familiar with basic physics formulas?

Here are some ideas for starters:
1. There is a small coefficient of friction between the ice and the goalie's skates. You could assume that the total energy needed is W = Fd = (uN)d = (umg)d.
2. You could relate this to the kinetic energy equation, K = 1/2mv^2, to determine the needed velocity v. You may be disappointed with the result using just the ideas from 1 and 2, since you don't see these results to be true.
3. When the puck impacts with the goalie, this will produce a torque about the goalie's center of mass.

Another idea is to compute the required torque necessary to overcome the friction of the ice/skates and knock the goalie flat on his back and go from there.
 
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