Bullet Through Ballistic Pendulum- Please help me

shigami117

1. A 9.05- g bullet from a 9-mm pistol has a velocity of 331.0 m/s. It strikes the 0.705- kg block of a ballistic pendulum and passes completely through the block. If the block rises through a distance h = 19.47 cm, what was the velocity of the bullet as it emerged from the block? i know that this is supposed to be done using conservation of energy and momentum. but i can't get it

mgb_phys

It's still a conservation of energy.

Initial kinetic energy of bullet + initial potential energy of block (which is zero) -> final ke of bullet + final potential energy of block.