Weight & Tension Helo 2 Tension

by d1343
Tags: helo, tension, weight
d1343 is offline
Jan27-09, 02:40 PM
P: 3
1. The problem statement, all variables and given/known data

How to find Weight in this problem?
I am trying to do this statics problem
but I don't know how to find the weight
so I can solve for
Sum Fy = 0
here is the picture link

2. Relevant equations
sum of Fx = 0
480 cos(30) - 450 = 0

sum of Fy = 0
480 sin(30) - W = 0
how do I find the weight to substract it

3. The attempt at a solution

I dont know I am like really stuck
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LowlyPion is offline
Jan27-09, 02:46 PM
HW Helper
P: 5,346
Resolve the tensions into their X and Y components.

The system is static, so the sum of the X forces must equal 0 and sum of the Y as well.

Be careful. One of the tensions may not be critical to holding up the weight.
d1343 is offline
Jan27-09, 02:57 PM
P: 3
wht the equation I wrote is not right?
Sum of the Force in X = 480 cos(30) - 450 = 0
I get = 415 - 450
= -34
Sum of the Force in y = 480 sin (30) - W = 0
240 -w = 0

I how do I solve for weight
the answer is about 259.81 lb
& there is also for t2

ΣFx = 0; 480cos(30) − 450 = 0

ΣFy = 0; 480sin(30) − W = 0

(F ab2 W2) = Find (FAB W)

W2 = 240.00 lb
W= min (W1 W2) = W 240.00 lb

LowlyPion is offline
Jan27-09, 04:11 PM
HW Helper
P: 5,346

Weight & Tension Helo 2 Tension

You have 2 tensions to worry about.

Like the weakest link - that's where it will break right?

First figure out which is the critical constraint.

If T1 = 450 max, what does that translate to for the chain that can withstand 480? Will the 450 break if it's 480, or will the 480 break if it's 450?

Then you are armed with what you need to know, because from your equations, you can see that whatever the T1, the weight it can support is 1/2 T1.

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