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Question why is there a negative sign |
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| Feb7-09, 10:56 PM | #1 |
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Question why is there a negative sign
A particle moves along the c axis. its position is given by the equation x = 2+3t-4t^2, with x in meters and t in seconds. Determine (a) its position when it changes direction and )b) its velocity when it returns to the position it had at t = 0.
i understand how to get (a) but for (b) im confused why in the solution they put -x = -2-3t+4t^2 why is the negative there, i understand there is a change in direction at 0, im confused why the negative sign is there can you give me a clear and understanding reasoning. thank you. |
| Feb8-09, 01:23 AM | #2 |
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I have no clue. They just randomly decided to flip the signs on everything, it looks like =/
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