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Trace of a matrix equals sum of its determinants?

 
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Feb8-09, 03:42 PM   #1
 

Trace of a matrix equals sum of its determinants?

If a matrix is diagonalizable, how does its trace equal the sum of its eigenvalues?

I can't find a proof for this anywhere.
 
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Feb8-09, 03:43 PM   #2
 
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What is the trace of a diagonal matrix? What are the algebraic properties of trace?
 
Feb9-09, 08:44 AM   #3
 
Ah I see, the trace is similarity invariant. thanks
 
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