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Improper Integral

by Lchan1
Tags: improper, integral
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Feb8-09, 03:48 PM
P: 39
1. The problem statement, all variables and given/known data
Determine if the integral converges or diverges?
it;s the integral of 0 to infinity
of 1/(1+x^6)^(1/2)

2. Relevant equations

so I compared it with 1/x^2

3. The attempt at a solution

the answer key says it converges but i think it diverges since the integral of 1/x^2 diverges from 0 to 1...
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Feb8-09, 04:17 PM
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P: 25,251
1/x^2 is WAY GREATER than 1/(1+x^6)^(1/2) near 0. In fact, the latter function is bounded on [0,1]. The fact 1/x^2 diverges near zero doesn't prove your function does.

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