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Ideal hcp lattice, ratio c/a = 1.633 proof
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Feb9-09, 10:09 AM
1. The problem statement, all variables and given/known data
q: show that for an ideal hcp structure the c/a ratio is equal to (8/3)^(1/2) = 1.633
this question has come up before in the forum but still it has not fully answered:
Dec30-05, 12:27 AM
This is the mathematical calculation ^ means to the power of
c/2 = a/2 Then a^2 /2 = c^2/2
a^2 + a^2
----- = (4R)^2
-------------- = 16 R^2
3a^2 = 2 *16 R^2
a^2 = 2*16 R^2
a = 2* square root of 16 divided by square root of 3
a = 8 / 3 = 1.6329 R
Jan26-06, 06:48 PM
The assumptions above are roughly correct, but we have to take into the considerations the Pythagorean Theorem.
The Pythagorean Theorem states: b^2=a^2+c^2. as well as c/2 or half of hexagonal crystal structure as well as the cosine for 30 degree triangles generated by the hole in Hexagonal closed packed.
So we write:
c/a half of this c/2.
Cos 30 degree
Feb9-09, 03:49 PM
i have tried. the last post by Kouros Khamoushi almost worked...
how ever i do not understand where some of the steps....
1. c/2 = a/2??? how?
2. 3a^2 = 2 *16 R^2???? where in the world did the factor of 3 come from on the LHS of this eqn.
You are prob correct... however please clarify the steps as i am totally baffled.
ps. inha: what shape of slice do u mean? also i hope it is from hexagonal lattice?
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