
#1
Feb1209, 01:47 PM

P: 2

Hi there!
I'm a new student to physics and i'm still learning a lot about it. Our teacher recently gave a question and i'm not sure how to work out the answer, can anyone help me? So here it goes: Here's a waterfall (See pic), the water at the bottom of the waterfall is 1C hotter than the water at the top of the waterfall. How would I work out a value for h? Please see picture below for diagram Any help much appreciated! Here is my attempt at solving the problem: E = MC (delta) theta = (Mass of water) (4200) ( theta + 1)  Potential energy = mgh = M(9.8)(h) > 9.8mh = 4200 (mass)( theta + 1) > 9.8h = 4200( theta + 1) 



#2
Feb1209, 03:15 PM

HW Helper
P: 5,346

Welcome to PF.
4200 or 4186 the method looks sound. 



#3
Feb1209, 04:24 PM

P: 2





#4
Feb1209, 06:31 PM

HW Helper
P: 5,346

Working out a value for H!?Examine then the ΔE which by your equation can be written as ΔE = m*C*ΔT mgh = mC*ΔT gh = C*ΔT For a 1° change then h = C/g 


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