# Working out a value for H?

by echoindia756
Tags: working
 P: 2 Hi there! I'm a new student to physics and i'm still learning a lot about it. Our teacher recently gave a question and i'm not sure how to work out the answer, can anyone help me? So here it goes: Here's a waterfall (See pic), the water at the bottom of the waterfall is 1C hotter than the water at the top of the waterfall. How would I work out a value for h? Please see picture below for diagram Any help much appreciated! Here is my attempt at solving the problem: E = MC (delta) theta = (Mass of water) (4200) ( theta + 1) -------------------------------------------- Potential energy = mgh = M(9.8)(h) --> 9.8mh = 4200 (mass)( theta + 1) --> 9.8h = 4200( theta + 1)
 HW Helper P: 5,343 Welcome to PF. 4200 or 4186 the method looks sound.
P: 2
 Quote by LowlyPion Welcome to PF. 4200 or 4186 the method looks sound.
Right I understand that but I can't seem to get any further than the above.

HW Helper
P: 5,343
Working out a value for H?

 Quote by echoindia756 Right I understand that but I can't seem to get any further than the above.
Sorry I thought you had it.

Examine then the ΔE which by your equation can be written as

ΔE = m*C*ΔT

mgh = mC*ΔT

gh = C*ΔT

For a 1° change then

h = C/g

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