# Power and heaters

by jakey
Tags: heaters, power
 P: 51 1. The problem statement, all variables and given/known data A heater rated at 2000W operating at 250V is used on a supple of 230V. if the resistance of the heater will not be affected by temp, what is the power absorbed by the heater? 2. Relevant equations i think that the only equation to use will be P=V^2/R 3. The attempt at a solution because the resistance of the heater is its internal property, i would first compute for the resistance from: R=(230^2)/2000. afterwhich, i would compute the power absorbed by the heater through: V=250-230=20 -> P = (20^2)/R which will be computed from the previous equation. is this right? thanks!
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P: 11,912
 Quote by jakey R=(230^2)/2000
Not quite. At 230 V, the power will be different than 2000 W.

 A heater rated at 2000W operating at 250V ...
So, P is 2000W when V=?
P: 51
 Quote by Redbelly98 Not quite. At 230 V, the power will be different than 2000 W. So, P is 2000W when V=?
oh sorry. so, i think it shouldve been R=V^2/P and V=250V while P=2000W.

so, the power when it operates at 230V is simply P= 230^2/R and the answer I would subtract from 2000W? is it right? thanks

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P: 11,912

## Power and heaters

 Quote by jakey oh sorry. so, i think it shouldve been R=V^2/P and V=250V while P=2000W. so, the power when it operates at 230V is simply P= 230^2/R
Yes, correct up to this point.

 and the answer I would subtract from 2000W? is it right? thanks
Uh, no. The problem statement asks for the power when V=230V. So just use the power you get from
P= 230^2/R
... and that's the final answer.
P: 51
 Quote by Redbelly98 Yes, correct up to this point. Uh, no. The problem statement asks for the power when V=230V. So just use the power you get fromP= 230^2/R... and that's the final answer.
lol, i misinterpreted the question. thanks, really!!!:D

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