Which Charge Do I Use for Calculating Capacitance?

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SUMMARY

The capacitance of a capacitor can be calculated using the formula C = Q/V, where Q represents the charge and V represents the potential difference. In the case discussed, with charges of +1500 C and -1500 C and a potential difference of 300 V, the absolute value of the charge (1500 C) should be used to ensure a positive capacitance value. Thus, the capacitance is calculated as C = 1500 C / 300 V, resulting in a capacitance of 5 F. This confirms that capacitance is always expressed as a positive value, regardless of the charge's sign.

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  • Knowledge of voltage and potential difference
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I just need a hint on this.

2 plates of a capacitor hold +1500 C and -1500 C of charge, respectively, when the potential difference is 300 V. What is the capacitance?

I know I have to use c=Q/V, but which charge do I use the positive or negative?
 
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First of all, you can't have a negative capacitance. Second of all, all capacitors will have both a negatively charged and positively charged side, I'm pretty sure, so you should notice since capacitance is always given positive, that you should give it as a positive value. I didn't really like Electronics, so I can't remember or care to get my textbook, but you can look this stuff up (possibly in your text) and figure out how capacitors work, what voltage is, etc, and that way you'll understand why it's positive.
 


You will need to use the absolute value of both charges, as the capacitance is a measure of the amount of charge stored on each plate. So in this case, the capacitance would be calculated using 1500 C as the charge value. Remember to also use the potential difference of 300 V in your calculation.
 

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