Solving for Spring Constant and Distance in Falling Elevators Problem

  • Thread starter Thread starter suffian
  • Start date Start date
  • Tags Tags
    Falling
Click For Summary
SUMMARY

The discussion revolves around solving the spring constant and compression distance for a falling elevator scenario, specifically redesigning the elevator safety system as described in Example 7-11. The mass of the elevator is 2000 kg, with an initial speed of 25 m/s and a kinetic friction force of 17,000 N. The correct spring constant required is 919 N/m, and the distance compressed when the elevator stops is 39.8 m. The maximum acceleration of the elevator is calculated to be 17.0 m/s², confirming the design's practicality.

PREREQUISITES
  • Understanding of work-energy principles in physics
  • Familiarity with spring mechanics and Hooke's Law
  • Knowledge of static and kinetic friction concepts
  • Ability to solve quadratic equations
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn about Hooke's Law and its applications in engineering
  • Explore static and kinetic friction calculations in mechanical systems
  • Practice solving quadratic equations in physics problems
USEFUL FOR

Students and professionals in mechanical engineering, physics enthusiasts, and anyone involved in designing safety systems for elevators or similar mechanical systems.

suffian
edit::
nm, i figured it out. i forgot to account for the weight of elevator in the "If static friction.. " part. thanks anyway. I'm sorry i can't delete the post.
::edit

I hit a brick wall over yet another problem concerning energy methods, basically a mismatch between my answer and the book's. I would appreciate whoever has the time to look this over and guess where I might be going wrong.

Anyway, here's the problem verbatim:

Redesign the elevator safety system of Example 7-11 [A falling elevator stopped by a powerful spring] so that the elevator does not bounce but stays at rest the first time its speed becomes zero. The mass of the elevator is 2000 kg and its speed when it first touches the spring is 25 m/s. There is a kinetic friction force of 17,000 N and the maximum static friction on the elevator is also 17,000 N. The mass of the spring can be neglected. a) What spring constant is required, and what distance is the spring compressed when the elevator is stopped? Do you think the design is practical? Explain. b) What is the maximum magnitude of the acceleration of the elevator?

Book Ans: a) 919 N/m, 39.8 m b) 17.0 m/s^2

Begin with work-energy formula:
[tex]\begin{align*}<br /> \Delta K =& \, W_\text{gravity} + W_\text{friction} + W_\text{spring} \\<br /> 0 - \frac{1}{2}mv^2 =&\, mgX - fX - \frac{1}{2}kX^2<br /> \end{align*}[/tex]

Quadratic formula to find compression distance X (neglect neg ans):
[tex] X = \frac{1}{k} (mg - f + \sqrt{ (mg-f)^2 +kmv^2 }) [/tex]

If static friction will hold elevator at X, then it follows:
[tex]F = kX \leq f \text{ or } X \leq \frac{f}{k}[/tex]
[tex] X = \frac{1}{k} (mg - f + \sqrt{ (mg-f)^2 +kmv^2 }) \leq \frac{f}{k}[/tex]

Manipulate to find assertion about spring constant:
[tex]k \leq \frac{f}{mv^2} (3f - 2mg)[/tex]
[tex] k \leq \frac{[17000 \text{ N}]}{[2000 \text{ kg}][25 \text{ m/s}]^2} (3[17000 \text{ N}] - 2[2000 \text{ kg}][9.80 \text{ m/ss}]) [/tex]
[tex]k \leq 160 \text{ N/m}[/tex]

So, answer is not the same.

edit::
nm, i figured it out. i forgot to account for the weight of elevator in the "If static friction.. " part. thanks anyway. I'm sorry i can't delete the post.
::edit
 
Last edited by a moderator:
Physics news on Phys.org


Great job on solving the problem! It's always a good feeling when we figure out where we went wrong and are able to correct it. Don't worry about not being able to delete the post, it's a learning process and others may benefit from seeing how you approached and solved the problem. Keep up the good work!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
42
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
7
Views
2K