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Wave question - stretched string |
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| Mar24-09, 03:39 PM | #1 |
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Wave question - stretched string
1. The problem statement, all variables and given/known data
A stretched string has length L and is attaached to a rigid support at either end. The string displacement from equilibrium at t=0 is given by: y(x,0) = sin(3(pi)x/L) and the velocity of the string is: y'(x,0) = (3pi/L)sqrt(T/rho)sin(3(pi)x/L) where T = tension in the string, and rho = its mass per unit length and sqrt(T/rho) is the wave velocity of transverse waves on the string. Give the form of the displacement y for all x, t. 2. Relevant equations (This is kind of where I'm stuck). I assumed the general equation of a wave was y = sin(kx)cos(wt), but that didn't work. I then tried with y = sin(kx-wt), but that also didn't seem to work. 3. The attempt at a solution I tried to use the general equation for a wave, differentiate it wrt t, plug in t=0 and compare it to the given velocity equation, but whenever I try I end up with a cos term instead of sine. I really can't figure out how it's a sine term in both the displacement and velocity. If I used y = sin(kx)sin(wt), then at t=0, y=0. And if I used y = sin(kx)cos(wt), then dy/dt = -wsin(kx)sin(wt), and at t=0, dy/dt = 0. If I used y = sin(kx-wt), then dy/dt = wcos(kx-wt), which doesn't have the necessary sine term. Any ideas? |
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| Mar24-09, 04:25 PM | #2 |
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You should take as your general solutions both sine an cosine terms:
y= sin(kx)[A sin(wt) +B cos(wt)] terms. Or equivalently work with a phase shift sin(kx)sin(wt+p). |
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