Newton's Second Law & Moment of Inertia Derivation?by danyalasdf Tags: derivation, inertia, moment, newton 

#1
Mar2909, 11:35 AM

P: 6

1. The problem statement, all variables and given/known data
We did something very similar to this in lab http://webenhanced.lbcc.edu/physte/p...%20Inertia.pdf Use Newton's Second to derive the expression for the experimentally determined moment of inertia 2. Relevant equations Newton's Second Law is F=m*a s=(1/2)*a*t^2 Experimentally Moment of Inertia I=r^2(m((gt^2/2s)t)  mf) Trying to get to this ^ mf= mass effective not much meaning just mass in kg If it confusing the gt^2 is divided by 2s then it is subtracted by t and multiplied by r^2 and then minus mf Torque= F*r= m*r*a T= (mf + m)(g  a) = tension 3. The attempt at a solution T= (mf + m)(g  (2*s/t^2)) T= (mf + m)((1/2)(a*t^2)  a) T= (mf + m)(a((1/2)*t^2  1) I am stuck write here 



#3
Mar2909, 12:04 PM

P: 6





#4
Mar2909, 12:23 PM

PF Gold
P: 4,182

Newton's Second Law & Moment of Inertia Derivation?
Calc may not be necessary.
So what's the physical system you're doing in this problem? Is it the same exact system as in the lab? 



#5
Mar2909, 01:12 PM

P: 6




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