| Thread Closed |
Another Derivate |
Share Thread |
| Jun12-04, 03:33 PM | #1 |
|
|
Another Derivate
Thanks for your help....
How about this one? Using the definition of derivate find f ` (x) f(x) = x/(2x-1) f ` (x) = lim h->0 [(f(x+h)) – (f(x))]/h lim h->0 ([((x+h) / (2x+2h-1))-(x/(2x-1))]/h) . [((2x+2h-1)(2x-1)) / ((2x+2h-1)(2x-1))] lim h->0 [(2x^2)-x+(2xh)-h-(2x^2)-(2hx)+x]/(h(2x+2h-1)(2x-1)) lim h->0 -h/(h(2x+2h-1)(2x-1)) = -1/(2x-1)^2 |
| Jun12-04, 03:37 PM | #2 |
|
|
If f(x)=x/(2x-1), then it is correct.
|
| Jun12-04, 03:42 PM | #3 |
|
|
yes...thanks
|
| Jun12-04, 03:48 PM | #4 |
|
|
Another Derivate
just a suggestion, ladyrae:
if you have more questions on this, don't open any new thread, continue to use this instead. In addition, try to learn LATEX formatting, it's not very difficult.. |
| Thread Closed |
Similar discussions for: Another Derivate
|
||||
| Thread | Forum | Replies | ||
| Prooving derivate of x^n | Calculus | 8 | ||
| Derivate question | Calculus & Beyond Homework | 2 | ||
| Derivate of geometrical product | Introductory Physics Homework | 4 | ||
| Derivate of x^p | Calculus | 1 | ||
| Derivate of Factorial | Calculus | 3 | ||