- #1
ladyrae
- 32
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Thanks for your help...
How about this one?
Using the definition of derivate find f ` (x)
f(x) = x/(2x-1)
f ` (x) = lim h->0 [(f(x+h)) – (f(x))]/h
lim h->0 ([((x+h) / (2x+2h-1))-(x/(2x-1))]/h) . [((2x+2h-1)(2x-1)) / ((2x+2h-1)(2x-1))]
lim h->0 [(2x^2)-x+(2xh)-h-(2x^2)-(2hx)+x]/(h(2x+2h-1)(2x-1))
lim h->0 -h/(h(2x+2h-1)(2x-1)) = -1/(2x-1)^2
How about this one?
Using the definition of derivate find f ` (x)
f(x) = x/(2x-1)
f ` (x) = lim h->0 [(f(x+h)) – (f(x))]/h
lim h->0 ([((x+h) / (2x+2h-1))-(x/(2x-1))]/h) . [((2x+2h-1)(2x-1)) / ((2x+2h-1)(2x-1))]
lim h->0 [(2x^2)-x+(2xh)-h-(2x^2)-(2hx)+x]/(h(2x+2h-1)(2x-1))
lim h->0 -h/(h(2x+2h-1)(2x-1)) = -1/(2x-1)^2
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