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Another Derivate

by ladyrae
Tags: derivate
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ladyrae
#1
Jun12-04, 03:33 PM
P: 32
Thanks for your help....

How about this one?

Using the definition of derivate find f ` (x)

f(x) = x/(2x-1)

f ` (x) = lim h->0 [(f(x+h)) (f(x))]/h

lim h->0 ([((x+h) / (2x+2h-1))-(x/(2x-1))]/h) . [((2x+2h-1)(2x-1)) / ((2x+2h-1)(2x-1))]

lim h->0 [(2x^2)-x+(2xh)-h-(2x^2)-(2hx)+x]/(h(2x+2h-1)(2x-1))

lim h->0 -h/(h(2x+2h-1)(2x-1)) = -1/(2x-1)^2
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arildno
#2
Jun12-04, 03:37 PM
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If f(x)=x/(2x-1), then it is correct.
ladyrae
#3
Jun12-04, 03:42 PM
P: 32
yes...thanks

arildno
#4
Jun12-04, 03:48 PM
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P: 12,016
Another Derivate

just a suggestion, ladyrae:
if you have more questions on this, don't open any new thread, continue to use this instead.
In addition, try to learn LATEX formatting, it's not very difficult..


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