Register to reply

Differentiating natural logs and exponential functions?

Share this thread:
Mirth
#1
Apr13-09, 03:12 PM
P: 23
Hey all, I'm really having a hard time figuring out a couple of problems in which I have to differentiate:

1: [tex] \frac{e^3^x}{\ln x} [/tex]

I just don't know how to put it together... I know that [tex]e^3^x[/tex] is [tex]3e^3^x[/tex], and I know that you can't different [tex]\ln x[/tex], so I dunno what to do from there...

And:

2: [tex] \ln(e^-^2^x + e^-^x)[/tex]

Totally not sure what to do there... Any help would be appreciated, I've looked online for similar examples and couldn't really find anything relevant to help me. Thanks!
Phys.Org News Partner Science news on Phys.org
An interesting glimpse into how future state-of-the-art electronics might work
Tissue regeneration using anti-inflammatory nanomolecules
C2D2 fighting corrosion
Hootenanny
#2
Apr13-09, 03:43 PM
Emeritus
Sci Advisor
PF Gold
Hootenanny's Avatar
P: 9,772
Let's take the first question first,
Quote Quote by Mirth View Post
Hey all, I'm really having a hard time figuring out a couple of problems in which I have to differentiate:

1: [tex] \frac{e^3^x}{\ln x} [/tex]

I just don't know how to put it together... I know that [tex]e^3^x[/tex] is [tex]3e^3^x[/tex]
Correct.
Quote Quote by Mirth View Post
and I know that you can't different [tex]\ln x[/tex], so I dunno what to do from there...
Erm... yes you can!

HINT: Let y = lnx, then x = ey. Now differentiate x = ey with respect to x.
Mirth
#3
Apr13-09, 04:18 PM
P: 23
Quote Quote by Hootenanny View Post
Let's take the first question first,

Correct.

Erm... yes you can!

HINT: Let y = lnx, then x = ey. Now differentiate x = ey with respect to x.
Hrm, I'm feeling a bit retarded so bear with me, hehe. So, [tex]\frac {1}{x}[/tex]?

Hootenanny
#4
Apr13-09, 04:20 PM
Emeritus
Sci Advisor
PF Gold
Hootenanny's Avatar
P: 9,772
Differentiating natural logs and exponential functions?

Quote Quote by Mirth View Post
Hrm, I'm feeling a bit retarded so bear with me, hehe. So, [tex]\frac {1}{x}[/tex]?
Correct

So as far as putting it all together, can you suggest anything? Perhaps some sort of rule...?
Mirth
#5
Apr13-09, 04:50 PM
P: 23
I'm really retarded at math, ugh... Hehe. So I have [tex]\frac {3e^3^x}{1/x}[/tex] ... Pretty sure I'm lost on what to do from there. :(
Hootenanny
#6
Apr13-09, 04:57 PM
Emeritus
Sci Advisor
PF Gold
Hootenanny's Avatar
P: 9,772
Quote Quote by Mirth View Post
I'm really retarded at math, ugh... Hehe. So I have [tex]\frac {3e^3^x}{1/x}[/tex] ... Pretty sure I'm lost on what to do from there. :(
No that is not correct.

[tex]\frac{d}{dx} \frac{f\left(x\right)}{g\left(x\right)} \neq \frac{f^\prime\left(x\right)}{g^\prime\left(x\right)}[/tex]

What 'rules' of differentiation do you know?
Mirth
#7
Apr13-09, 06:43 PM
P: 23
Not sure of any rules by name... I'm going to have to research more examples, I'm so rusty in math that I am unsure...
Hootenanny
#8
Apr14-09, 02:38 AM
Emeritus
Sci Advisor
PF Gold
Hootenanny's Avatar
P: 9,772
Quote Quote by Mirth View Post
Not sure of any rules by name... I'm going to have to research more examples, I'm so rusty in math that I am unsure...
Try searching for the quotient rule, or the product rule and chain rule.
Mirth
#9
Apr14-09, 04:18 PM
P: 23
I kinda give up on the first one, heh... Can someone tell me if I have #2 right?:

Answer: [tex]\frac {1 - e^-^2^x}{e^-^x + e^-^2^x} [/tex]
Pengwuino
#10
Apr14-09, 05:01 PM
PF Gold
Pengwuino's Avatar
P: 7,120
Quote Quote by Mirth View Post
I kinda give up on the first one, heh... Can someone tell me if I have #2 right?:

Answer: [tex]\frac {1 - e^-^2^x}{e^-^x + e^-^2^x} [/tex]
The quotient rule and product rule explains how to differentiate two functions that divide are divided by or multiplied by eachother. Just look that up and identify f(x) and g(x) (that is the standard notation at least).

For #2, it isn't correct. What did you do to come up with that answer?
slider142
#11
Apr14-09, 05:03 PM
P: 898
Mirth, can you show us step by step how you differentiated that expression?
tiny-tim
#12
Apr15-09, 08:14 AM
Sci Advisor
HW Helper
Thanks
tiny-tim's Avatar
P: 26,148
Hi Mirth!
Quote Quote by Mirth View Post
Not sure of any rules by name...
ok, do you recognise this one by face

(fg)' = ?


Register to reply

Related Discussions
Natural Logs and inverse functions Calculus & Beyond Homework 2
Functions + Natural Logs Precalculus Mathematics Homework 6
Differentiating Logarithmic and Exponential Functions Calculus & Beyond Homework 10
Differntiating natural logs of x and y functions Precalculus Mathematics Homework 6
Differentiating natural logs Precalculus Mathematics Homework 5