What would this curve look like? (hot air balloon problem)

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SUMMARY

The discussion focuses on the relationship between the temperature inside a hot air balloon and its diameter, specifically aiming to lift 400 pounds. The volume of the balloon is calculated using the formula V = πD³/6, assuming a spherical shape. Additionally, the ideal gas law (PV = nRT) is applied to understand how temperature affects the density of the air inside the balloon. The optimum temperature for lifting is noted to be just below the boiling point of water, with ambient air at 5 degrees Celsius.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of basic geometry (volume of a sphere)
  • Familiarity with temperature scales (Kelvins and Celsius)
  • Concept of buoyancy and lifting power in hot air balloons
NEXT STEPS
  • Research the effects of temperature on gas density in hot air balloons
  • Explore calculations for lifting power based on balloon volume and air density
  • Study the relationship between ambient temperature and hot air balloon performance
  • Investigate safety regulations and optimal operating conditions for hot air balloons
USEFUL FOR

Aerospace engineers, hot air balloon operators, physics students, and anyone interested in the mechanics of buoyancy and thermodynamics in aviation.

Terminus
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I'm just wondering what a curve would look like if the x-axis is the temperature inside a hot air balloon and the y-axis is the diameter (in feet) of the balloon. There's a relation in how many pounds a hot air balloon can lift based on this curve and I'm looking to see what a good balance would be between both x and y to be able to lift 400 pounds into the air.
 
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Terminus said:
I'm just wondering what a curve would look like if the x-axis is the temperature inside a hot air balloon and the y-axis is the diameter (in feet) of the balloon. There's a relation in how many pounds a hot air balloon can lift based on this curve and I'm looking to see what a good balance would be between both x and y to be able to lift 400 pounds into the air.

Let's take a shot at this. I think you only need two formulas.

Assume the balloon takes on a spherical shape, so it's Volume is
[tex]V = \frac{\pi D^3}{6}[/tex]

And assuming the air inside the balloon acts as an ideal gas
[tex]P V = n R T[/tex]

Once the balloon is fully expanded, the pressure is constant, so as the temperature (in Kelvins) increases, the number of gas molecules in the balloon decreases proportionally. So the change in density of the heated air is inversely proportional to the differnce in temperature between the ambient air and the air inside the balloon.

I understand the optimum temperature for the air inside a hot air balloon is just under the boiling point of water. Assume the outside air is a chill 5 degrees C.

If you knew the mass of the air contained in the volume of the balloon, that should be enough to calculate the lifting power.

Is that close enough?
 

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