How much charge stored in capacitor ?

ixtra

A paper is placed between two plates of copper , area 100 cm^2. The thickness of the paper 0.005cm and its dielectric constant is 2.5 . If the paper can bear an electric field of 5 x 10^5 V/cm then calculate the maximum voltage upto which the capacitor can be charged.How much charge will be stored on the capacitor ?



My attempt -> A=100cm^2
K=2.5
5x10^5=9x10^9 x q / r

LowlyPion

Welcome to PF.

First figure the capacitance
ε = 2.5*ε_o
C = ε*A/d = 2.5*8.8*10^-12*(.01 m²)/.00005m

Then you can use that result to figure the charge at max V with

Q = v*C

ixtra

thanks