How Do Forces Balance When Standing on Tiptoe?

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SUMMARY

The discussion focuses on the mechanics of standing on tiptoe, specifically analyzing the forces involved when the total gravitational force (Fg) is 700 N. Participants clarify that the force exerted by the floor (n) equals the gravitational force, and they emphasize the importance of equilibrium in the system. The forces exerted by the achilles tendon (T) and the tibia (R) are also critical to solving the problem, with suggestions to take vertical and horizontal force components and moments about a specific point for analysis.

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Homework Statement


When a person stands on tiptoe (a strenuous position), the position of the foot is as shown in Figure P8.16a. The total gravitational force on the body, Fg, is supported by the force n exerted by the floor on the toes of one foot. A mechanical model of the situation is shown in Figure P8.16b, where T is the force exerted by the achilles tendon on the foot and R is the force exerted by the tibia on the foot. Find the values of T, R, and theta when Fg = 700 N.

for the picture go here http://qaboard.cramster.com/physics-topic-5-1064-cpi0.aspx

Figure P8.16


Homework Equations





The Attempt at a Solution


i'm really confused...
 
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wowdusk said:
The total gravitational force on the body, Fg, is supported by the force n exerted by the floor on the toes of one foot. A mechanical model of the situation is shown in Figure P8.16b, where T is the force exerted by the achilles tendon on the foot and R is the force exerted by the tibia on the foot. Find the values of T, R, and theta when Fg = 700 N.

Hi wowdusk! :smile:

n = Fg = 755N (or is it 700N? I'm confused :confused:).

The foot is in equilibrium, so everything should add to zero.

Take components of force vertically and horizontally, and also take moments of force about some point (I suggest the end of the R force). :wink:

What equations do you get?
 

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