
#1
May509, 07:56 PM

P: 3

1. The problem statement, all variables and given/known data
a piece of metal of 10cm X 20 cm X 5 cm is sitting flat on the bottom of water basket, with one of the 10cm X 20cm sides facing up. the metal has density of 19.3 g/cm3. The basket is filled with water(full). The backet has a radius of 0.25m and a hight of 1m, density of water 1g/cm3. What is the total force acting on the metal? a) 9800N b) 196 N c) 19.3 N d) 1.00N e) none of the above 2. Relevant equations P = pgh, F= PA 3. The attempt at a solution The question asks for total force. So i first assumed they are asking for total net force. Considering the bottom of the metal does not touch water, i think there is no bouyancy. So the only net force acting on it is the pressure from water above the metal. The surface area = 0.2 m X 0.1m = 0.02 m2 depth of water = 0.95m volume of water above the metal v = 0.95X0.02 = 0.019 m3 Gwater = 0.019 X 1000kg/m3 X 9.8 n/kg = 186.2 N but there is no 186.2 N in the question, i did it using P = pgh and still gets the same thing, what could it be? 



#2
May509, 09:38 PM

P: 3

omg someone plz HELP!!!




#3
May609, 12:00 PM

P: 3

please?



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