## Electric Field of Coaxial Cable

After working it out myself, I have the logarithim part equal to:

[ln b - lna] + [ln c - ln b] = [ln b/a + ln c/b] = ln c/a (Not sure about this statement!)

I don't understand where the c^2 and ab came from with this integral?

Any help?

Thanks!

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 Quote by Lavace After working it out myself, I have the logarithim part equal to: [ln b - lna] + [ln c - ln b] = [ln b/a + ln c/b] = ln c/a (Not sure about this statement!) I don't understand where the c^2 and ab came from with this integral? Any help? Thanks!
Take a careful look at the factors in front of each logarithm (they are different by a factor of 2) and remember that $p\ln(x)=\ln(x^p)$