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How much pop from a Kitewing? |
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| May11-09, 08:37 PM | #1 |
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How much pop from a Kitewing?
There's a product on the market called a Kitewing. It's a hand held sail for ice, water or land. It can be swung horizontally to lift. I'm curious to know how much mimium wind speed would be needed to get some pop?
There are some utube videos out where some get 5 ft of air from level ground. Suprizing for such a small wing. The sail is symmetric like a wing, having a 5.5 square meters, with an aspect ration of about 2.2, and a roughly eliptical profile. Wing span and washout aren't given. |
| May12-09, 11:26 PM | #2 |
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So I guess there aren't any AEs around who have any interest in fluid flows without a cabin wraped around them and 500+ horses in the front...
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| May12-09, 11:38 PM | #3 |
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Your question doesnt leand itself to a simple answer. Aerodynamics is highly experimental. There isnt a magic formula you can use to arrive at the answer you want.
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| May14-09, 12:34 AM | #4 |
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How much pop from a Kitewing?
I've run out of time. I'll have to generate some numbers tomorrow afternoon.
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| May15-09, 08:58 PM | #5 |
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Mg = ½CLρV²S ρO = 1.225 kg/m³, density of air at sea level ρ = 1.1 kg/m³ CL_MAX=1.2 V = 30 mph = 44 fps = 13.4 m/s S = 5.5 m² g = 9.8 m/s², acceleration due to gravity. M = 67 kg Mg = 146 lb ...very marginal. For a sail on land, we could assume a "beta" of at least 30 degrees. This means wind speed is 15 mph to obtain a 30 mph relative wind, V at the most favorable tack. The ground speed would be 30*0.866 mph. For a wing that is mostly single sided except along the leading edge, I'm assuming a max coefficient of lift of only 1.2. I still don't know if I'm using the right coefficient of lift. CL_MAX is the lift coefficient of an infinite aspect ration section. |
| May15-09, 11:04 PM | #6 |
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Sorry, that's way wrong. You want 'not too close' build or use a wind tunnel, or find data generated by someone who has. You've pretty much assumed 99.9% of the problem. Your answer is probably as much as 40% off.
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| May16-09, 09:56 AM | #7 |
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You're estimating on the Cl and treating like an infinite wing. Of course it's going to be off, but, IMO, for a first guess, those numbers don't seem all that bad. At least you aren't in the area of an order of magnitude off. Especially since you are treating Cl as a constant (which it isn't) and who knows just what the relative velocity a wing actually sees is. As a total SWAG I think you're not too bad. Just understand that to be accurate you need way more information.
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| May16-09, 10:23 AM | #8 |
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| May16-09, 03:47 PM | #9 |
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Recognitions:
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| May16-09, 05:05 PM | #10 |
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