I'm not sure of your math-stat background in this problem, so bear with me.
For a big sample size

has approximately a normal distribution, right? You can approximate the distribution of

(it will also turn out to be a normal distribution - look in (say) Hogg/Craig or any introductory math stat book for the idea, or write back and I can put the method here), and then you can get an approximate confidence interval for
Note - just so I don't have to post it:
If an estimate

for some parameter

satisfies
(the

means "tends to a normal distribution as

- i.e., it represents convergence in distribution)
then for a function

that is continuous and has a non-zero derivative at

it is true that
Your statistic is the sample proportion, the parameter is

, and the function is