# Uncertainty propagation visible light spectrum

by zdenton
Tags: light, uncertainty, wavelength
 P: 5 1. The problem statement, all variables and given/known data I have conducted an experiment which attempts to calculate the range of the visible light spectrum. Basically white light was shined through a diffraction grating (300 lines/mm) and diffraction theory is applied to calculate the wavelength. So, here are the variables: $$d=\frac{1}{300000}$$ $$l=0.20$$ $$\Delta l=0.001$$ $$y=0.043$$ $$\Delta y=0.005$$ 2. Relevant equations $$\sin\alpha=\frac{\lambda}{d}$$ $$\tan\alpha=\frac{y}{l}$$ 3. The attempt at a solution I combined these equations to end up with: $$\lambda=d\times\sin\left(\arctan\left(\frac{y}{l}\right)\right)$$ The problem is that I don't know how to estimate an uncertainty for this equation. I know that for simple equations like $$y=q\times r$$ the uncertainty is $$\Delta y=\left(\frac{\Delta q}{q}+\frac{\Delta r}{r}\right)\times y$$. Unfortunately I don't know how to apply this to a more complex equation. If anyone could lead me in the right direction as to an equation which would give the uncertainty for $$\lambda=d\times\sin\left(\arctan\left(\frac{y}{l}\right)\right)$$, it would be greatly appreciated.
 Mentor P: 11,911 It can be done using calculus, if you've had calculus. But first I would get rid of the trig functions. What's an equivalent expression for sin(arctan(x)) ?
 P: 5 $$\frac{x}{x^{2}+1}$$ Substituting $$\frac{y}{l}$$ for $$x$$ gives: $$\frac{\frac{y}{\left|y\right|}\times l}{\sqrt{y^{2}+l^{2}}}$$ I hadn't thought of doing this, so it seems to be a step in the right direction. I have done limited calculus, I'm just finishing the first year of IB Math HL so we're starting on integration right now. I looked briefly at the wikipedia page for error propagation and didn't really understand it.
HW Helper
P: 2,156

## Uncertainty propagation visible light spectrum

FYI, here's the usual case: if you have a function $$f(x, y, z)$$ and the uncertainties in the arguments are $$\delta x$$, $$\delta y$$, and $$\delta z$$, then the uncertainty in $$f$$ is
$$\delta f = \sqrt{\left(\frac{\partial f}{\partial x}\delta x\right)^2 + \left(\frac{\partial f}{\partial y}\delta y\right)^2 + \left(\frac{\partial f}{\partial z}\delta z\right)^2}$$
 P: 5 OK, thanks for the help so far. I applied the above formula to my equation and received the following result: $$\delta f = \sqrt{{\delta l}^{2}\,{\left( -\frac{d\,\left| l\right| \,y}{{l}^{2}\,\sqrt{{y}^{2}+{l}^{2}}}+\frac{d\,y}{\left| l\right| \,\sqrt{{y}^{2}+{l}^{2}}}-\frac{d\,\left| l\right| \,y}{{\left( {y}^{2}+{l}^{2}\right) }^{\frac{3}{2}}}\right) }^{2}+{\delta y}^{2}\,{\left( \frac{d\,\left| l\right| }{l\,\sqrt{{y}^{2}+{l}^{2}}}-\frac{d\,\left| l\right| \,{y}^{2}}{l\,{\left( {y}^{2}+{l}^{2}\right) }^{\frac{3}{2}}}\right) }^{2}}$$ Substituting with the variables in my first post returns the result: $$\delta f = 7.79\times 10^{-8}$$ Which is exactly what I received when I tried using an online uncertainty calculator! Thank you so much!