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Old Jun6-09, 09:34 PM                  #1
evagelos

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regorous and formal proof of (-1).x =-x

Give a rigorous and then a formal proof of the theorem :

LaTeX Code: \\forall x [ (-1).x = -x ]
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Old Jun6-09, 09:51 PM                  #2
mXSCNT

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Re: regorous and formal proof of (-1).x =-x

Hint: (-1).x = -x means that (-1).x + x = 0
This should be in a homework forum
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Old Jun6-09, 10:21 PM                  #3
evagelos

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Re: regorous and formal proof of (-1).x =-x

Originally Posted by mXSCNT View Post
Hint: (-1).x = -x means that (-1).x + x = 0
This should be in a homework forum
Meaning that formal proofs are homework stuf??
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Old Jun7-09, 06:50 AM       Last edited by HallsofIvy; Jun7-09 at 06:57 AM..            #4
HallsofIvy

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Re: regorous and formal proof of (-1).x =-x

Once again, we return to the question, "What do you mean by 'formal proof'?"

I think you are just talking about the kind of proof you would find in a math paper or calculus book- far from what, say, logicians would mean by "formal proof". A true "formal proof" of such a thing would probably require an entire book! How many pages did Russel and Whitehead require to prove "1+ 1= 2"?

Another question: what algebraic system are you working in? The proof for an abstract ring or integral domain would be quite different than for the real numbers.

MXSCNT's point is that the only good reason for doing such "fiddly" stuff is practise: homework.
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Old Jun7-09, 07:32 AM                  #5
Preno

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Re: regorous and formal proof of (-1).x =-x

It would be something like:

0.x = 0
(-1+1).x = 0
-1.x + 1.x = 0
-1.x + x = 0
-1.x = -x
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Old Jun7-09, 07:43 PM                  #6
evagelos

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Re: regorous and formal proof of (-1).x =-x

Originally Posted by HallsofIvy View Post
Once again, we return to the question, "What do you mean by 'formal proof'?"
The definition was given in another thread by tgt and is the following:

Originally Posted by tgt View Post
I would mean the kind that most people (at least all the logicians) would regard as formal.

A formal proof or derivation is a finite sequence of sentences (called well-formed formulas in the case of a formal language) each of which is an axiom or follows from the preceding sentences in the sequence by a rule of inference. The last sentence in the sequence is a theorem of a formal system.

.
With the only difference that i may add:

each formula could be, apart from axiom, a theorem or definition


Originally Posted by HallsofIvy View Post
I think you are just talking about the kind of proof you would find in a math paper or calculus book- far from what, say, logicians would mean by "formal proof". A true "formal proof" of such a thing would probably require an entire book! How many pages did Russel and Whitehead require to prove "1+ 1= 2"?
Go to pages 121 to 139 in ANGELO'S MARGARIS book :

FIRST ORDER MATHEMATICAL LOGIC.There you will find many true "formal proofs" not more than half a page long

You know how many books you need before you double integrate a function ,or write a proof in analysis??

Originally Posted by HallsofIvy View Post
Another question: what algebraic system are you working in? The proof for an abstract ring or integral domain would be quite different than for the real numbers.

MXSCNT's point is that the only good reason for doing such "fiddly" stuff is practise: homework.
On the following axiomatic system i will base any formal or rigorous proofs:

The primitive symbols are:
= for equality
+ for addition
. for multiplication
- for the inverse in addition
0 constant
1 constant
/ for inverse in multiplication

LaTeX Code:  1\\neq 0
AND the axioms are:

1) LaTeX Code: \\forall a\\forall b[ a+b = b+a].......\\forall a\\forall b[ a.b = b.a ]

2)LaTeX Code: \\forall a\\forall b\\forall c[ a+(b+c) = (a+b)+c]........\\forall a\\forall b\\forall c[ a(bc)=(ab)c]


3)LaTeX Code: \\forall a[ a+0 = a]............\\forall a[ 1.a =a]


4) LaTeX Code: \\forall a[ a+(-a) = 0]..........\\forall a[ a\\neq 0\\Longrightarrow a.\\frac{1}{a} = 1]<BR> .



5)LaTeX Code: \\forall a\\forall b\\forall c [ a(b+c) = ab + ac]


AND now the rigorous proof of (-1)x = -x



(-1)x = (-1)x + 0 =................................................. ............by axiom 3 (for addition)

=(-1)x +[ x + (-x)]=................................................. ............by axiom 4 (for addition)

=[(-1)x +x] + (-x) =................................................. ............by axiom 2 (for addition)

=[(-1)x + 1x] + (-x)=............................................... ..............by axiom 3 (for multiplication)


=[x.1 + x(-1)] + (-x)=............................................... .............by axiom 1 ( for addition and multiplication)


=[ x( 1 + (-1))] + (-x)=............................................... ..........by axiom 5


= x.0 + (-x) = .................................................. ....................by axiom 4 (for addition)


= 0 + (-x) =................................................. ......................by the theorem 0.x = 0


= -x .................................................. ............................by axiom 4 (for addition)

Next post the formal proof
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Old Jun8-09, 01:18 PM                  #7
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Re: regorous and formal proof of (-1).x =-x

Sounds like homework to me.
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Old Jun8-09, 01:47 PM                  #8
CRGreathouse

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Re: regorous and formal proof of (-1).x =-x

Originally Posted by HallsofIvy View Post
How many pages did Russel and Whitehead require to prove "1+ 1= 2"?
360. But it's complicated only if you're trying to prove that equation under R or C; if you restrict yourself to Peano arithmetic it follows from the definition of 2 and the symmetry of equality.
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