Magnitude or direction of a vector

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Homework Help Overview

The discussion revolves around vector analysis in a two-dimensional context, specifically focusing on the magnitude and direction of vectors related to a scenario involving navigation and orientation skills. Participants are examining the components of vectors derived from a scout troop's movements.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to calculate the x and y components of vectors based on given distances and angles. Questions arise regarding the accuracy of their calculations and the interpretation of vector directions.

Discussion Status

Some participants have identified errors in their calculations and are seeking clarification on the correct approach to determine vector components. There is an ongoing exploration of different interpretations of vector direction and component calculations.

Contextual Notes

Participants are working under the constraints of homework problems that require precise calculations of vector components based on specified angles and distances. There is a noted ambiguity in the description of one vector's direction.

akatsafa
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Can someone please tell me what I'm doing wrong?

I drew a picture of this triangle, but I'm not coming up with the right magnitude or direction. it says a scout troop is practicing it orienreering skills with map and compass. First they walk due east for 1.2 km. Next, they walk 45 degrees west of north for 2.7km. How far and in what direction must they walk to go directly back to their starting point.

I'm getting the x component of A to be 1.2 and the y component of A to be 0. I'm getting the x component of B to be 2.7cos45 and the y component of B to be -2.7 sin 45. But I'm not getting the right answer. Please help!
 
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Let u = (1.2, 0) and v = (-2.7cos(45), 2.7sin(45)) be the given vectors. The location of the scouts is basically u + v. To get back to the starting point, the scouts need to reverse their location, which is just -(u + v). Dead simple. Maybe you have problems calculating the magnitude and direction of this vector. What did you get as an answer?
 
thank you. i had the negative signs switched. i had it as 2.7cos(45) and -2.7sin(45). Also, for another problem i got the y component right but the x component is wrong. It says if a vector is 20 m long and makes an angle 60 degrees counterclockwise from the y-axis, what are the x and y components. I got -10 as the y component and 17.3 as the x component, but the x component is wrong. Do you know what I'm doing wrong?
 
akatsafa said:
It says if a vector is 20 m long and makes an angle 60 degrees counterclockwise from the y-axis, what are the x and y components. I got -10 as the y component and 17.3 as the x component, but the x component is wrong. Do you know what I'm doing wrong?
Your response looks OK to me, although your description of the vector is somewhat ambiguous. What are you supposed to get?
 

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