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Angular momentum and Linear momentum elastic collision

 
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Aug16-09, 03:45 PM   #1
 

Angular momentum and Linear momentum elastic collision


1. The problem statement, all variables and given/known data
Ok so I have two objects of different masses [latex]{m}_{{1}}[/latex] for the projectile and [latex]{m}_{{2}}[/latex] for the spinning top. The projectile has only translational kinetic energy in the direction of the arrow (see attached image), with [latex]{v}_{{1}}[/latex] and [latex]{v}_{{2}}[/latex] as initial and final linear velocities, respectively the initial velocity is known but not the final one. It collides with a spinning top, which has [latex]{\omega }_{{1}}[/latex] and [latex]{\omega }_{{2}}[/latex] as initial and final angular velocities, the initial being known.
.
2. Relevant equations
Firstly there is no torque(I have already asked a few people and they mentioned torque), as the perpendicular distance of the projectile from the axis of the spinning top is 0.(so [latex]\tau =r\times F = 0[/latex])

Energy wise: [latex]{E}_{{before}}=\frac {1}{2}I{\omega }_{{1}}^{{2}}+\frac {1}{2}{m}_{{1}}{v}_{{1}}^{{2}}[/latex]

[latex]{E}_{{after}}=\frac {1}{2}{m}_{{1}}{v}_{{2}}^{{2}}+\frac {1}{2}{m}_{{2}}{v}_{{s2}}^{{2}}+\frac {1}{2}I{\omega }_{{2}}^{{2}}[/latex]
vs2 is the final velocity of the spinning top.
The elastic collision equations found at wikipedia are also relevant.


3. The attempt at a solution
Well I know how to solve collisions, but only when they are exclusively linear or angular.

I have basically used the conservation of energy principle, solving first in 1D(is that possible, or do I have to solve in 2d? And in 2d, how would you do it taking account of the angular velocity of the spinning top?) which obviously left me without answer.

Considering solving in 2D, I based myself on this:
http://www.myphysicslab.com/collision.html
but I am not sure it would work for a spinning top, could anyone advise me on how to use these equations but with a spinning top?
So basically I am a lost, could anyone help out/ give me some possible directions to explore?

Thanks in advance...
PS: This is unrelated but could the admins please remove the automatic adding of the template each time the thread is previewed, its really annoying :) (or maybe its just a problem with vBulletin)
Attached Thumbnails
Collision.jpg  
 
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Aug16-09, 04:23 PM   #2
 
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Hi Unperfect! Welcome to PF!

(have an omega: ω )
Quote by Unperfect View Post
Firstly there is no torque(I have already asked a few people and they mentioned torque), as the perpendicular distance of the projectile from the axis of the spinning top is 0.(so [latex]\tau =r\times F = 0[/latex])
If there's no torque, why would ω change?
PS: This is unrelated but could the admins please remove the automatic adding of the template each time the thread is previewed, its really annoying :) (or maybe its just a problem with vBulletin)
Do you mean that if you preview n times, you get n+1 templates?
 
Aug16-09, 04:55 PM   #3
 
Quote by tiny-tim View Post
Hi Unperfect! Welcome to PF!

(have an omega: ω)
Thanks!(and thx for the ω also, I couldn't be bothered to find the ascii code for it :P)
Quote by tiny-tim View Post
If there's no torque, why would ω change?
Thats maybe were I'm getting things wrong, but maybe I should explain a bit further; I am also doing this as an experiment for a project and in the experiment the spinning top's ω reduces upon impact(by about 200-300 rpm my tachometer tells me, with a reasonably fast projectile) and "ejects" the projectile back at an angle(around pi/4 rad). But having the data is not enough(well for me at least, maybe the teacher just wants that), I also want to know the theory behind(and possibly program a simulation).
So anyway while googling and asking away about change in ω, I found that most people's reply involved torque but for torque to be non-zero(hence have an impact and be useable) the force applied by the projectile has to be at a distance perpendicularly from the spinning top's axis. But ideally(i'm sure its not perfect in my experiment) this distance is zero(see diagram in first post).
Maybe I should ask the question like this:
If I were to program a simulation of a collision in 2D of two objects of known mass and initial velocity and ω, one with exclusively KE and the other with exclusively RKE, what equations should I use to calculate the outcome?(most video games easily manage that but I dont know how :P) Does friction have to be taken into account?
Sorry if i'm making complicated but help is very much appreciated
Do you mean that if you preview n times, you get n+1 templates?
Thats exactly it, though I think it does check to see if the template is there(character by character) and if it's not(or has changed) it appends a template.
 
Aug17-09, 04:18 AM   #4
 
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Angular momentum and Linear momentum elastic collision


Quote by Unperfect View Post
I am also doing this as an experiment for a project and in the experiment the spinning top's ω reduces upon impact(by about 200-300 rpm my tachometer tells me, with a reasonably fast projectile) and "ejects" the projectile back at an angle(around pi/4 rad).

If I were to program a simulation of a collision in 2D of two objects of known mass and initial velocity and ω, one with exclusively KE and the other with exclusively RKE, what equations should I use to calculate the outcome?(most video games easily manage that but I dont know how :P) Does friction have to be taken into account?
Hi Unperfect!

(ooh, i didn't give you the full list … have a pi: π )

If the top "ejects" the projectile back at about 45º, then it looks as if friction is involved.

And perhaps you should try to measure the coefficient of restitution (the inelasticity) between the top and the object, with the top fixed (and rotating at various speeds, including zero)?

(btw, are you doing experimental physics, or computer science? In other words, are you actually trying to find out what happens, or are you just practising computer modelling?)
Thats exactly it, though I think it does check to see if the template is there(character by character) and if it's not(or has changed) it appends a template.
I've noticed that some members post two or even three templates, and I've always wondered why!

After a quick search in the Feedback sub-forum, I now see it's a well-known bug that we just have to put up with … see http://www.physicsforums.com/showthr...plate+homework
 
Aug18-09, 09:26 AM   #5
 
Quote by tiny-tim View Post
(ooh, i didn't give you the full list … have a pi: π )
Thanks, but I do use my wacom tablet which(quite accurately surprisingly) transcripts whatever math I write in it into latex code so I can my symbols if I really need them :P.
Quote by tiny-tim View Post
If the top "ejects" the projectile back at about 45º, then it looks as if friction is involved.
Yeah, friction is involved, it can't have possibly been something else; what was i thinking?
Anyway I decided to try a second approach, I'm not sure if it's a correct reasoning though.

Can I consider a single point on the spinning top(the one where the impact with the projectile occurs.[ie, red point on attached diagram]) and consider it to have a linear velocity(as demonstrated by the green line) calculated using v=rω.
Then can I consider that point on the spinning top to have a linear momentum of [latex]
{p}_{{2}}={m}_{{2}}r{\omega }_{{1}}
[/latex]?
With this I can resolve in 2D the collision that occurs and sure enough if I do this, torque is present(well a direction in that movement at least).
I solve a sample problem assuming 100% elasticity and I got a similar result to what you can see in diagram 3(the arrows with a black stroke are the resultant velocities).

No I have another problem; I do not know the magnitude of the force to resolve
[latex]
\tau =r\times F
[/latex].
because I have no measure of the time of impact, I can only calculate the change in momentum...

Quote by tiny-tim View Post
And perhaps you should try to measure the coefficient of restitution (the inelasticity) between the top and the object, with the top fixed (and rotating at various speeds, including zero)?

(btw, are you doing experimental physics, or computer science? In other words, are you actually trying to find out what happens, or are you just practising computer modelling?)
I'm not sure exactly if I can measure the restitution coefficient, I do have two photogates so I could measure it but that might complicate the process, I might assume it to be 1 and then comment on that assumption in the evaluation.

And I'm doing experimental physics, but I would like to program a simulation so as to compare the results to comment(this is for an Extended Essay[a component of the IB Diploma]).

Thanks
Attached Thumbnails
Collision2.jpg   Collision3.jpg  
 
Sep1-09, 05:24 AM   #6
 
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Hi Unperfect!

I'm very sorry I haven't replied earlier …

your pictures hadn't come up yet when I first looked, nor when I checked back, and after that I forgot to check again.
Quote by Unperfect View Post
Can I consider a single point on the spinning top(the one where the impact with the projectile occurs.[ie, red point on attached diagram]) and consider it to have a linear velocity(as demonstrated by the green line) calculated using v=rω.
Then can I consider that point on the spinning top to have a linear momentum of [latex]
{p}_{{2}}={m}_{{2}}r{\omega }_{{1}}
[/latex]?
With this I can resolve in 2D the collision that occurs and sure enough if I do this, torque is present(well a direction in that movement at least).
I solve a sample problem assuming 100% elasticity and I got a similar result to what you can see in diagram 3(the arrows with a black stroke are the resultant velocities).
I really don't like short-cuts like that …

they probably don't work (and does it take into account the rotational energy of both bodies?), but even if they do, it tends to take longer to check that they work than it would to do it the standard way.
Now I have another problem; I do not know the magnitude of the force to resolve
[latex]
\tau =r\times F
[/latex].
because I have no measure of the time of impact, I can only calculate the change in momentum...

I'm not sure exactly if I can measure the restitution coefficient, I do have two photogates so I could measure it but that might complicate the process, I might assume it to be 1 and then comment on that assumption in the evaluation.
You can calculate the torque (or rather the torque-impulse) from the change in energy of the top.

(But do you need the torque? Isn't conservation of angular and linear momentum enough?)

I think you do need a realistic figure for the restitution coefficient … say to the nearest .05 … so that you can write a reasonably accurate conservation of energy equation (and don't forget that the friction will rotate the projectile also. ).

I suspect that finding the restitution coefficient with a non-spinning top is probably accurate enough.
 
Sep8-09, 11:24 AM   #7
 
Quote by tiny-tim View Post
Hi Unperfect!
I think you do need a realistic figure for the restitution coefficient … say to the nearest .05 … so that you can write a reasonably accurate conservation of energy equation (and don't forget that the friction will rotate the projectile also. ).

I suspect that finding the restitution coefficient with a non-spinning top is probably accurate enough.
Thank you for your help; I can get the restitution coefficient quite easily actually.
But again the problem I have is calculating this collision theoretically; but I'll sort that out with my physics teacher I think.
If you think you can help, well all I need is a way to calculate the outcome of a collision of objects with rotational and kinetic energy(that is, ignoring all the post collision data I can collect) in 2 dimensions, provided I know all the starting variables(ie. elasticity coefficient, celocity, angular velocity,mass etc.) because I have yet to find a physics textbook which provides me with equations/guidance on handling such problems.

Anyway, thank you very much for your help.
 
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