Sketching x/[(1+3x)^2-1]


by Jules18
Tags: 3x21, sketching, x or 1
Jules18
Jules18 is offline
#1
Sep30-09, 10:36 PM
P: 102
x/[(1+3x)^(1/2)-1]

I'm wondering if it's even possible to imagine what a graph of this fxn would look like, or do you definitely need a graphing calc?

When I plug it into a TI83, it ends up looking pretty linear and apparently doesn't exist when x < 0

~Jules~



PS. sorry for how messy the eq'n looks, it's difficult to type. ... (1+3x) should be under a sqrt. sign.
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Bohrok
Bohrok is offline
#2
Sep30-09, 11:28 PM
P: 867
Just by looking at it, you see that you have x in the numerator and x1/2 in the denominator. For large x, the function will roughly look like x1/2, but you can find a better approximation. After multiplying the top and bottom of the fraction by the conjugate of the denominator and doing some work on it, you get

[tex]\frac{\sqrt{3x + 1} + 1}{3} = \frac{\sqrt{3x(1 + \frac{1}{3x})} + 1}{3} = \frac{\sqrt{3x}\sqrt{1 + \frac{1}{3x}}}{3} ~+~ \frac{1}{3} = \frac{\sqrt{3}}{3}\sqrt{x} \sqrt{1 + \frac{1}{3x}} ~+~ \frac{1}{3}[/tex]

As x→∞, the larger radicand goes to 1 and has less and less effect on √x, so the function is nearly like [tex]\frac{\sqrt{3}}{3}\sqrt{x} ~+~ \frac{1}{3}[/tex]
Jules18
Jules18 is offline
#3
Oct6-09, 02:13 PM
P: 102
thanks ^_^


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