I don't know how to find the normal force on this problem

xstetsonx

1. A m = 3.0 kg wood box slides down a vertical wood wall while you push on it at a θ = 49° angle. What magnitude of force should you apply to cause the box to slide down at a constant speed?

2. Fk-Mk*n


3. i know there are 4 forces acting on the object. gravity, normal force from the wall, kinetic friction, and the force that i applied. but i do not know how to set up the equation to solve this problem

Vykan12

Do you know how to draw a free body diagram?

xstetsonx

yea i did one but the n is on the x axis so that means i need to know the F to get the normal force right?

Vykan12

First off, you have to neglect friction since you do not know the kinetic friction coefficient of the surface. Second, the normal force doesn't cause the block to move in what you defined to be the x direction. Are you using newton's second law for net force in the x and y directions?

xstetsonx

o i am sorry this question some how expected us to find the coefficient of kinetic friction on wood which is 0.2. and yes

tiny-tim

Hi xstetsonx! Welcome to PF!
No, you don't need to know F, you can just call it F.

For constant speed, you need zero acceleration, which means zero net force in both the x and y direction.

So call the force F, find N, and then find µN.

xstetsonx

so the total force will be
mK*Fcos49-mg+Fsin49?

tiny-tim

Yes, except I'm not sure about that m at the beginning.

Vykan12

You should get

[tex]F_{app} - F_{k} - mg\sin(\theta) = 0[/tex]
[tex]n - mg\cos(\theta) = 0[/tex]

The algebra's up to you.

Edit:

Yes, that's correct, assuming F is the force of gravity.