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unifrom distribution of a disc |
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| Oct28-09, 01:13 PM | #1 |
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unifrom distribution of a disc
1. The problem statement, all variables and given/known data
[tex]\D = \{(x,y) \in \mathbb{R}^2 | x^2 + y^2 \leq 1\} [/tex] i.e. a disc or radius 1. Write down the pdf f_{xy} for a uniform distribution on the disc. 2. Relevant equations 3. The attempt at a solution [tex] f_{xy} = \frac{(x^2 + y^2)}{\pi} \mbox{for} x^2 + y^2 \leq 1[/tex] 0 otherwise as the area of the disc pi and to make it uniform you divide by pi so the probability integrates to 1 |
| Oct28-09, 02:25 PM | #2 |
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Hmmm...
[tex] f_{xy} = \frac{(x^2 + y^2)}{\pi}[/tex] Doesn't look very uniform to me
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| Oct28-09, 03:17 PM | #3 |
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i think i got it: its [tex]
f(x,y)_{xy} = \left\{ \begin{array}{rl} \frac{1}{\pi} &\mbox{for } x^2 + y^2 \leq 1\\ 0 &\mbox{otherwise} [/tex] thanks |
| Oct28-09, 03:25 PM | #4 |
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Recognitions:
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unifrom distribution of a disc
Looks good to me!
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| Oct26-10, 03:20 PM | #5 |
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I am doing a some practice questions for stats and i tried to integrate this to get 1 but i can't so what are the appropriate limits and how would i go about finding the marginal distribution of x and y? Thanks
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| disc, distribution, probability density, statistics |
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