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Current through a Resistor 
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#1
Nov1809, 12:34 PM

P: 24

1. The problem statement, all variables and given/known data
In the circuit the emf is 150V connected across a resistance network. Each resistor has a value of 10 ohms. What is the current through R2? 2. Relevant equations R=V/I 3. The attempt at a solution I found that the resistance of R2 and R3 because they're in a series is 20 ohms. And because R1 is parallel to R2 and R3 i found the resistance to be 6.67 ohms. So the total resistance of the circuit would be 16.67 ohms including R4. And then I found that the total current drawn from the emf would be 8.998A. Now I'm just not sure how to isolate R2's current. 


#3
Nov1809, 12:42 PM

P: 24

Would it be 120.2 V?



#5
Nov1809, 12:52 PM

P: 24

using the resistivity of R2 and R3 i multiplied it by the total current to find the potential drop and subtracted it from the emf voltage



#6
Nov1809, 01:00 PM

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#7
Nov1809, 01:26 PM

P: 24

So the current through R4 would be the sum of the current through R1, R2 and R3?
So could i just divide the current of 8.998 into 2? So that R1 will have a current of 4.499 and then divide 4.499 into 2 again so that R2 and R3 will have a current of 2.2495 each? 


#8
Nov1809, 01:32 PM

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P: 41,323

Find the voltage drop across R4, then use that to find the voltage across the R2+R3 branch. 


#9
Nov1809, 01:52 PM

P: 24

Okay, so for R4 I get a voltage drop of 89.98 so voltage across R2+R3 would be 60.02?
And then if i divide that by the total resistivity of R2+R3 i get 3.001, and since there's two i find that each resister will have 1.5 resistance? 


#10
Nov1809, 01:58 PM

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#11
Nov1809, 02:01 PM

P: 24




#12
Nov1809, 02:08 PM

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#13
Nov1809, 02:22 PM

P: 24

I get it now! Thanks for working this through with me!



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