# Double Integral with base e

by r_swayze
Tags: base, double, integral
 P: 66 $$\int_0^1\int_0^y e^{x^2} dx dy$$ The region I am integrating over should look like this graph, right? I tried switching the bounds but I am left where what I started. since 0 < x < y, and 0 < y < 1 I can switch to 0 < x < 1 , and x < y < 1 leaving me with the integral $$\int_0^1\int_x^1 e^{x^2} dy dx$$ integrating gives ex2y then substituting the values for y gives $$\int_0^1 e^{x^2} - e^{x^2}x dx$$ Am I integrating over the wrong bounds? I know if 0 < y < x, it would work. Attached Thumbnails