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Double Integral with base e 
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#1
Nov2009, 12:08 PM

P: 66

[tex]
\int_0^1\int_0^y e^{x^2} dx dy [/tex] The region I am integrating over should look like this graph, right? I tried switching the bounds but I am left where what I started. since 0 < x < y, and 0 < y < 1 I can switch to 0 < x < 1 , and x < y < 1 leaving me with the integral [tex] \int_0^1\int_x^1 e^{x^2} dy dx [/tex] integrating gives e^{x2}y then substituting the values for y gives [tex] \int_0^1 e^{x^2}  e^{x^2}x dx [/tex] Am I integrating over the wrong bounds? I know if 0 < y < x, it would work. 


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