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Digital Electronics: State machine 
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#1
Nov2509, 03:39 AM

P: 90

1. The problem statement, all variables and given/known data
(a) How many states does this system have? (b) How many rows will there be in a state transition table? (c) Provide the state transition table. (d) Draw a state diagram of the system. (e) Describe what the circuit does in words. 2. Relevant equations 3. The attempt at a solution a) I think there are two flip flops (or are they switches?), so that means that there are four states: 00, 01, 10, and 11. b) I think the state transition table will have 8 rows. These numbers will be at the beginning of each row: 000 001 010 011 100 101 110 111 


#2
Nov2509, 05:38 PM

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P: 40,729

Show us what you end up with! 


#3
Nov2609, 05:18 AM

P: 90

A B Y Next X Next Y
0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 I'm a little bit confused as to what to do after this. I see the equation AB'Y + A'BY' going into J and K. So that means that J and K will always be the same. Is that right? 


#4
Nov2609, 07:53 AM

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P: 40,729

Digital Electronics: State machine



#5
Nov2609, 05:29 PM

P: 90

When both J and K are 0, then there is no change in outputs.
When they are both 1, then the outputs are toggled. A B Y Next X Next Y 0 0 0 I still get stuck at this part. I can tell that next Y is going to be 0, but I can't say what next X is, because the table doesn't tell me what X currently is. Another question. Is the circuit a Mealy machine, since the output is going back into the input? 


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