
#1
Dec209, 11:47 AM

P: 47

1. The problem statement, all variables and given/known data
Heya, I can expand the term on the LHs and get the term on the RHS no problem :) But, I don't understand how the bottom line is arrived at; I think its basically just a backward engineering of the product rule, but I can't get it! Any help would be useful 



#2
Dec209, 01:02 PM

P: 937

[tex] \frac{\partial(\rho u u)}{\partial x} = \rho u \frac{\partial u}{\partial x} + u \frac{\partial (\rho u)}{\partial x}. [/tex]




#3
Dec209, 03:28 PM

P: 47

Thanks
That was easier than I thought! 


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