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Momentum Flux: Quick Question (Product Rule)

by andrew.c
Tags: flux, momentum, product, rule
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andrew.c
#1
Dec2-09, 11:47 AM
P: 47
1. The problem statement, all variables and given/known data
Heya,
I can expand the term on the LHs and get the term on the RHS no problem :)
But,
I don't understand how the bottom line is arrived at; I think its basically just a backward engineering of the product rule, but I can't get it!

Any help would be useful
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clamtrox
#2
Dec2-09, 01:02 PM
P: 939
[tex] \frac{\partial(\rho u u)}{\partial x} = \rho u \frac{\partial u}{\partial x} + u \frac{\partial (\rho u)}{\partial x}. [/tex]
andrew.c
#3
Dec2-09, 03:28 PM
P: 47
Thanks
That was easier than I thought!


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