How Do I Solve Problems Involving Work and Kinetic Energy?

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Homework Help Overview

The discussion revolves around a physics problem involving work and kinetic energy, specifically focusing on two objects with different masses being pulled by the same net force over the same distance. The original poster expresses confusion regarding the relationship between work done and kinetic energy, as well as the mass of the second object.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how the work done on each object relates to their kinetic energies and questions the assumption that the work done on both objects is equal. They express uncertainty about calculating the kinetic energy of both objects and the mass of the second object.

Discussion Status

Some participants provide guidance by referencing the work-energy theorem and suggesting that the kinetic energy of object 1 is equal to the work done on it. There is an acknowledgment of the need to clarify assumptions about the forces acting on the objects and the implications for their kinetic energies.

Contextual Notes

The original poster indicates a lack of understanding of the formulas and concepts involved, particularly in calculating kinetic energy and mass based on the given information. There is a repeated emphasis on needing help and additional resources.

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HELP! energy and work TROUBLE!

:confused: :frown: ...im very worried about my current lesson in class because it has me completely stumped!

One questions asks...
Two objects move with different masses from rest and are pulled by the same magnitude net force and move through the same distance while the force acts on them. The work done on object 1 is 500 Joules (Nm). After the force has pulled each object, object 1 is moving twice as fast as object 2. Answer the following questions, showing your work.

(a) How much work is done on object 2? (i put the same amount, since the force and distance are the same in both, then work must be equal)

(b) What is the kinetic energy of object 1 AFTER being pulled? (this stumped me and i have no idea where to start)

(c) What is the kinetic energy of object 2 after being pulled? (i have no idea how to do c since b stumped me... :frown: )

(d) If the mass of object 1 is 20 kg, what is the mass of object 2?
(i put 20 kg for this answer, and i have no idea, nor formula, to show how i got it)

I NEED HELP! :confused: If u can help in ANY WAY please post a message for me! also, if u have useful links about this topic if u can post them i would really appreciate it! :redface:
THANKS!
 
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Physicshelpneeded said:
:confused: :frown: ...im very worried about my current lesson in class because it has me completely stumped!

One questions asks...
Two objects move with different masses from rest and are pulled by the same magnitude net force and move through the same distance while the force acts on them. The work done on object 1 is 500 Joules (Nm). After the force has pulled each object, object 1 is moving twice as fast as object 2. Answer the following questions, showing your work.

(a) How much work is done on object 2? (i put the same amount, since the force and distance are the same in both, then work must be equal)

(b) What is the kinetic energy of object 1 AFTER being pulled? (this stumped me and i have no idea where to start)

(c) What is the kinetic energy of object 2 after being pulled? (i have no idea how to do c since b stumped me... :frown: )

(d) If the mass of object 1 is 20 kg, what is the mass of object 2?
(i put 20 kg for this answer, and i have no idea, nor formula, to show how i got it)

I NEED HELP! :confused: If u can help in ANY WAY please post a message for me! also, if u have useful links about this topic if u can post them i would really appreciate it! :redface:
THANKS!

a) your right
b) use the work-energy theorem: work = change in mechanical energy. Assuming that the objects are moved in an horizontal path (so there is no change in potential energy) then ... work = change in kinetic energy.
so kinetic energy = 500J
c) the same as b. kinetic energy is 500J
d) for object 1:
m= 20 kg, K = 500 J
use equation K = (1/2) mv^2
solve for v, this will give you the velocity for object 1. Since the problem says that object 1 is moving twice as fast as object 2.
then: velocity of object 2 = velocity of object 1 divided by 2
 
work = change in mechanical energy.

The work in your equation is only that due to a nonconservative force. Gravity can do work on an object and not change the mechanical energy of the object.
 
THANKS visipavia, that helped a lot...thank u too john dubya
 

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