Calculating the Taylor Series for Arctan(x): Explained and Illustrated

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SUMMARY

The discussion focuses on calculating the Taylor Series for arctan(x) and its application in summing an alternating series. The series presented is (33/5) - (34/7) + (35/9) - (36/11) + ..., which can be expressed in terms of the Taylor Series for arctan(x) using the formula 3^3 * Σ(-1)^n * (3^n)/(2n + 5). Participants emphasize the importance of the alternating series test for convergence, clarifying that while the test can confirm convergence, it does not imply divergence if the test fails. The conversation highlights the concept of resummation methods to derive finite sums from divergent series.

PREREQUISITES
  • Understanding of Taylor Series, specifically for arctan(x)
  • Familiarity with alternating series and convergence tests
  • Knowledge of series manipulation techniques
  • Basic calculus concepts related to infinite series
NEXT STEPS
  • Study the Taylor Series for arctan(x) in detail
  • Learn about the Alternating Series Test and its applications
  • Research resummation methods for divergent series
  • Explore examples of series manipulation and convergence analysis
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Students preparing for calculus exams, mathematicians interested in series convergence, and anyone studying the properties of Taylor Series and alternating series.

vucollegeguy
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The series is:

(33/5) - (34/7) + (35/9) - (36/11)+...

Looking at this, I'm guessing I can use the Taylor Series for arctan(x) but I don't know how to apply it or where to begin.

Any help is greatly appreciated.
 
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You have 33/5 - 34/7 + 35/9 - 36/11 +...
= 33(1/5 - 3/7 + 32/9 - 33/11 +...)
=~3^3~\sum_{n = 0}^{\infty}(-1)^n~\frac{3^n}{2n + 5}

The series above is an alternating series. Do you know a test for determining whether such a series converges?
 
I can use the alternating series test where I let bn=(3n)/(2n+5), right?
 
The title of your post is "sum the series". I doubt that is what you mean. You probably mean test it for convergence.

Anyway, remember the alternating series test will only tell you a series is convergent. If the test for convergence fails, that does not tell you the series diverges. So the alternating series might not (hint, hint) be the end of the story for this problem.
 
Last edited:
This is what I'm confused about. This is a practice exam for my final. And question specifically says "Sum the following series."

I did what mark44 did and factored out the 3^(3) but I didn't come up with the sum formula. When I factored it out, it looked as if it were from the Taylor Series of arctan(x).

Now, I don't know where to go from here.
 
If you forget about convergence issues and want to "sum" the series in the sense of taking the Taylor expansion of some function and insert some value for x so that the expansion matches your series, then this is an example of a "resummation" method.

The idea is then that the series represents a finite number that was derived formally correctly, but it is an expansion around some point yielding a divergent series. But the terms of the expansion will contain all the information about the number which you have to "decode".

You are on the right track with the arctan function. If you look at two successive terms and forget about the missing terms at the start, what should you take for x?
 

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