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Airfoil pressure distribution |
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| Dec28-09, 09:09 PM | #1 |
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Airfoil pressure distribution
I am given a project to transform an airfoil from a cylinder using joukowski transform. The cylinder is in zeta plane and the airfoil is in z plane. I did the plotting and i got the airfoil shape using matlab. but i want to know how to plot the pressure distribution over the airfoil.
The inputs to my program are: Velocity, Angle of attack, coordinates of center of circle(zeta plane), radius of circle(zeta plane). Can somebody please tell me how to plot pressure distribution for an airfoil? I am using Matlab to do the stuff but i m getting weird plots for pressure distribution. Please help me of someone can...deadline near |
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| Dec29-09, 10:39 AM | #3 |
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Recognitions:
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Ah the Joukowski airfoil, once my bane. Are you having trouble solving for the pressure, or just displaying it?
I'm not real familiar with Matlab, I do most of my programming just in Fortran, so if it's displaying the results, perhaps the Math & Science Software board might be more appropriate. Otherwise, check out: http://en.wikipedia.org/wiki/Joukowsky_transform http://www.grc.nasa.gov/WWW/K-12/airplane/map.html |
| Dec29-09, 04:04 PM | #4 |
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Airfoil pressure distribution
Do your own work. This is easy stuff.
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| Dec30-09, 08:38 PM | #5 |
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| Dec30-09, 08:43 PM | #6 |
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| Dec30-09, 08:59 PM | #7 |
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What exactly do you need to do in terms of your code?
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| Dec30-09, 10:17 PM | #8 |
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I m stuck on how to write the loops for the points on airfoil where i have to plot the pressuer values
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| Dec30-09, 10:40 PM | #9 |
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[code]<copy paste your code here>[code] Replace the second code with /code for it work properly. Then you can explain what you are doing and what is going wrong. I've read about doing what you're asking in several books, but I have not implemented it, so I'll try and give a stab at it because I'd like to see it work. My background is flight dynamics and controls, not aerodynamics, so we need to be careful in doing things right. You will also have to supply me with the equations you are using, and what books they are coming from. |
| Dec30-09, 10:52 PM | #10 |
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[code]
clear all close all clc v_inf = input(' Enter the Speed [m/s]: '); v = v_inf/v_inf; alpha = input(' enter angle of attack [deg]: '); alpha = alpha*pi/180; s_x = input(' Circle Origin, X_0 [m]: '); s_y = input(' Circle Origin, Y_0 [m]: '); s = s_x + 1i*s_y; r = input(' Radius [m]: '); rho = 1.225; % TRANSFORMATION PARAMETER lambda = s_x + sqrt(r^2-s_y^2)%% this is the "C" in the currie book % CIRCULATION % beta = (alpha); % k = 2*r*v*sin(beta); % Gamma = k/(2*pi) %CIRCULATION %COMPLEX ASYMPTOTIC SPEED w = v * exp(1i*alpha); %TOLLERANCE % toll = +5e-4; % GENERATING MESH x = meshgrid(-10:.2:10); y = x'; % COMPLEX PLANE z = x + 1i*y; % Inside-circle points are Excluded! for a = 1:length(x) for b = 1:length(y) if abs(z(a,b)-s) <= r z(a,b) = NaN; end end end % JOUKOWSKI TRANSFORMATION, J = z+lambda^2./z; %GRAPHIC - Circle and Joukowski Airfoil angle = 0:.1:2*pi; z_circle = r*(cos(angle)+1i*sin(angle)) + s; z_airfoil = z_circle+lambda^2./z_circle; %Lift from KUTTA JOUKOWSKI THEOREM % L = v_inf*rho*Gamma; % L_str = num2str(L); %COEFFICIENT OF LIFT Cl=2*pi*(r./lambda)*sin(alpha+s_y./r) %Circulation necessary to satisfy Kutta Condition Kutta_C = 4*pi*v_inf*r*sin(alpha+asin(s_y/r)) %Chord Length c_length = max(real(z_airfoil))-min(real(z_airfoil)) %camber(curvature) h = 2*s_y %thickness t?? t = max(imag(z_airfoil))-min(imag(z_airfoil)) % complex POTENTIAL %f =w*(z) + (v*exp(-(1i)*alpha)*r^2)/lambda + 1i*k*log(z); % Coefficient of lift from circulation %lift force, Y = pro*v_inf*circulation %C_lift = Y/(1/2)*pro*v_inf^2*l C_lift = 2*Kutta_C/(v_inf*c_length) %Coefficient of lift from thickness, chord length and curvature approach in %currie Curr_cl = 2*pi*(1+0.77*(t/c_length))*sin(alpha+2*(h/c_length)) w_tilde = v_inf.*exp(-i.*alpha) + i.*Kutta_C./(2*pi.*((r-s)-z)) + v_inf.*(r.^2)*exp(i.*alpha)./(((r-s)-z).^2); w = w_tilde./(1 + (z-(r-s)).^2/(s.^2)); value = abs(w.^2); %aphi = (s.^2 - lambda^2)/s.^2; %PLOTTING SOLUTION figure(1) hold on %contour(real(z),imag(z),real(f),[-10:.5:10]); fill(real(z_circle),imag(z_circle),'b') axis equal axis on axis([-10 10 -10 10]) title(strcat('Circle')); figure(2) hold on % contour(real(J),imag(J),real(f),[-10:.5:10]) fill(real(z_airfoil),imag(z_airfoil),'b') axis equal axis on axis([-10 10 -10 10]) title('Transformed Airfoil'); P_airfoil = 99500 + 0.5*1.225*((v_inf.^2) - (abs(w).^2)); %Pressure distribution figure a = linspace(0,c_length,101); Cp = (P_airfoil - 99500)./(0.5*1.225*((v_inf.^2) - (abs(w).^2))); plot(a,Cp); %Coefficient of pressure % cp = 1 - 4*sin(t).^2 + 2* G / (pi*a*V_i) *sin(t) - (2* G/ (pi*a*V_i) )^2 ; [code] this program takes the coordinates of a cylinder in one plane and transforms it into an airfoil using the joukowski tranformation. The pressure distribution part is at the end. This is not working. I have no ideas on how to appraoch that. Sorry if i sound ignorant. |
| Dec30-09, 10:56 PM | #11 |
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First thing I will say, is ditch the user input at the command window. Have a variable for speed and AoA. Just set those variables before you hit run. You only really want user input if you are making something for other people to run. Every time you have to test your program, you waste time entering in values.
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| Dec30-09, 11:07 PM | #12 |
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[code]
clear all close all clc...[code] Actually, the way to do it is a [ code ] tag <your code> followed by a slashed code tag [ /code ] and leave out the spaces I've used to disable it. |
| Dec30-09, 11:57 PM | #13 |
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Can you explain this first block of code
Code:
v_inf = input(' Enter the Speed [m/s]: ');
v = v_inf/v_inf;
alpha = input(' enter angle of attack [deg]: ');
alpha = alpha*pi/180;
s_x = input(' circle Origin, X_0 [m]: ');
s_y = input(' Circle Origin, Y_0 [m]: ');
s = s_x + 1i*s_y;
r = input(' Radius [m]: ');
Also, what is s_x, s_y, and s? |
| Dec31-09, 12:36 AM | #14 |
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s_x and s_y are the coordinates of the center of the circle and r is the radius of the circle in a complex plane which i have to transform to an airfoil using joukowski transform.
s is he distance of the center of the circle from the origin. The imaginary part is there because this is a complex plane. i can define v as 1 but this doesnot make any difference |
| Dec31-09, 12:38 AM | #15 |
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'v=1' it is a bad habbit to do what you did because when someone looks at your code they are goign to wonder why you are dividing a variable by itself, and takes more computational power to perform a division operation than a declaration. These kinds of things are big no-nos in blade element or CFD code, where you have to do lots of operations/loops. Edit: Also, why do you have '1i'? I would rewrite your block of code as follows: Code:
%Convert degrees to radian d2r = pi/180; s %Define freestream velocity v_inf = 30; %[m/s] v = 1; %Define AoA alpha = 5*d2r; %Define transform coordinates s_x = 0.2; %[m] s_y = 0.2 %[m] s = s_x + i*s_y; r = 2; %[m] |
| Dec31-09, 12:38 AM | #16 |
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| Dec31-09, 12:46 AM | #17 |
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| Tags |
| aerodynamics, airfoil, fluid dynamics, matlab |
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