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Are these equivalent?by Zorodius
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#1
Aug304, 03:21 AM

P: 184

I'm sorry if this should be obvious to me, but it's not.
My book provides this equation for the bulk modulus: Equation 1: [tex]B = \frac{\Delta p}{\Delta V / V}[/tex] It says, by way of explanation, that it follows from a relationship they gave earlier: Equation 2: [tex]p = B \frac{\Delta V}{V}[/tex] (where p is the pressure, B is the bulk modulus, and V represents volume.) However, Equation 1 is easily rearranged into: Equation 3: [tex]B \frac{\Delta V}{V} =  \Delta p[/tex] Comparing equation 2 and 3 suggests: Equation 4: [tex]p =  \Delta p[/tex] Which is, as far as I can tell, complete nonsense. Are equation 1 and 2 really equivalent statements? If so, how? 


#2
Aug304, 08:03 AM

Mentor
P: 41,439




#3
Aug304, 09:02 AM

P: 184

Thanks a lot for the reply, I'm glad to know I'm not totally crazy yet.
Between this and other gems like "all friction is caused by cold welding" and "an element of a string oscillating in a transverse wave has maximum elastic potential energy at zero displacement" (both paraphrased, but exactly what the book claims), I'm about ready to conduct an experiment in inelastic collisions between this book and the garbage can 


#4
Aug304, 01:28 PM

P: 1,780

Are these equivalent?
Have you been able to locate an authentic errata which confirms this? Otherwise, the publishers should know about this. I suggest you refer to the older physics book by Resnick and Halliday (published sometime in the 60s)...volume 1 (the chapter on sound) and compare it with this edition's treatment. I think you might like the older one a shade better.
Cheers Vivek 


#5
Aug304, 02:33 PM

Mentor
P: 41,439

They aren't redefining the bulk modulus; they are just using "p" to represent the change from the undisturbed pressure [itex]p_0[/itex]. Make sense? 


#6
Aug304, 08:09 PM

P: 1,780

Great Doc!



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