# Proton in magnetic field

by TheDoorsOfMe
Tags: field, magnetic, proton
 P: 46 1. The problem statement, all variables and given/known data Proton moving in -y direction with a magnetic field pointing in the +y direction with a manitude of 5.0 T. The proton has a velocity of 3.01x10^7, What is the magnitude and direction of the magnetic force. 2. Relevant equations F=q(v x B) 3. The attempt at a solution The answer I think is either 0 or 1.5x10^8. I say it might be zero cause the cross product of anti-parallel vectors is zero right? Or I say its 1.5x10^8 because I just plugged into the above equation a solved. Which one is it? Or is it neither. 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution
PF Patron
P: 1,132
 Quote by TheDoorsOfMe 1. The problem statement, all variables and given/known data Proton moving in -y direction with a magnetic field pointing in the +y direction with a manitude of 5.0 T. The proton has a velocity of 3.01x10^7, What is the magnitude and direction of the magnetic force. 2. Relevant equations F=q(v x B) 3. The attempt at a solution The answer I think is either 0 or 1.5x10^8. I say it might be zero cause the cross product of anti-parallel vectors is zero right? Or I say its 1.5x10^8 because I just plugged into the above equation a solved. Which one is it? Or is it neither.