How Does General Relativity Redefine Light's Momentum and Force?

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Discussion Overview

The discussion centers around how general relativity (GR) redefines the concepts of light's momentum and force, exploring the implications of these changes in both classical and relativistic contexts. Participants examine the relationship between energy, momentum, and the electromagnetic spectrum, as well as the classical concept of radiation pressure.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant notes that in classical mechanics, light has no momentum because it has no mass, leading to the assumption that it cannot exert force.
  • Another participant proposes that in GR, light is considered to have momentum, referencing Einstein's suggestion that the electromagnetic spectrum could be viewed as matter.
  • A mathematical relationship is presented: p = E/c, where p is momentum and E is energy, prompting questions about the nature of energy in this context.
  • Discussion includes the derivation of momentum from energy using equations such as E^2 = m^2c^4 + p^2v^2, particularly for massless particles like photons.
  • Radiation pressure is mentioned as a classical phenomenon that demonstrates light's momentum, with references to historical contributions from figures like P.N. Lebedev.
  • Participants debate the classical understanding of radiation pressure and its relation to photons, with some asserting that classical electromagnetism can describe light's momentum without invoking quantum concepts.
  • Questions arise regarding the definitions of force and pressure, particularly how they relate to changes in momentum and time.
  • Clarifications are made about the role of the electric field in generating momentum effects when light interacts with surfaces, especially metallic ones.

Areas of Agreement / Disagreement

Participants express differing views on the classical versus modern interpretations of light's momentum and force. There is no consensus on whether classical electromagnetism fully accounts for these concepts without invoking photons, and the discussion remains unresolved regarding the definitions and implications of radiation pressure.

Contextual Notes

Some participants acknowledge limitations in their understanding of the underlying physics, and there are references to the necessity of basic electromagnetism knowledge to fully grasp the concepts discussed.

woodysooner
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In classical mech since light has no mass it had no p cause p=mv with m at 0 you have no momenum nor a force correct, by take the der.

But in GR, how is light considered to have momentum, I read somehting about Einstein saying that in the GR field EM spectrum could now be called matter. Wow interesting but how... just because EM now has momentum.

Also found

p = E/c which holds for a light-speed massless particle. is that E energy and if so pot or K or both just take - of the other.??

can someone derive this?

also in GR since the definition of momentum changed did also the definition of a force. That would include all Em spectrum to apply a force also light shined from a flashlight.

I know of radiation pressure felt by such things is this kind of like the force that is felt by a burst of photons falling on an object.

By no means am I qualified in any of this stuff just trying to learn, so feel free to hammer anything I have messed up in assuming or if my definitons are lacking horribly. But if anyone could answer a little of this I would be greatly appreciative.
 
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I think this is how its derived...
[tex]E = mc^2[/tex]
[tex]E/c = mc[/tex] (mc is mass times the velocity of light, which is momentum)
[tex]E/c = p[/tex]

I think there's another way to derive it, by using the total energy equation.
[tex]E^2 = m^2c^4 + p^2v^2[/tex]
Since the photon is moving at velocity c, and has mass 0, we plug those in...
[tex]E^2 = 0^2c^4 + p^2c^2[/tex]
[tex]E^2 = p^2c^2[/tex]
[tex]E^2/c^2 = p^2[/tex]
[tex]E/c = p[/tex]
 
wow, that was nicely done, thanks a lot.
 
E/c = P

but what is E/c are we calling that light

and what are the units for E/c
 
woodysooner said:
In classical mech since light has no mass it had no p cause p=mv with m at 0 you have no momenum nor a force correct, by take the der.

This is incorrect and a common misconception.

If you open a good E&M text, (example: Jackson's Classical Electrodynamics), you will encounter a section on "radiation pressure" exerted by light. This came about even with a purely classical treatment of light (i.e. not as photons) - a lot of this work was attributed to P.N. Lebedev. Since "pressure" implies a "change in momentum", this clearly shows that even the classical version of light also contains a description of light having a momentum.

Zz.
 
The E part of E/c is energy. The c part is the speed of light.

Energy is measured in Joules (Newton-meters or kg*m^2/sec^2).
The speed of light is measured in meters/sec.

That puts your momentum into kg*m/sec.

The E is found by multiplying the frequency times Planck's constant.

Planck's constant is about 6.626 x 10^-34 Joule seconds.
Frequency is measured in Hertz (cycles per second - the cycles are unitless, just as radians are).

Since blue light has a higher frequency than red light, blue light has more energy than red light, etc.
 
I know of radiation pressure felt by such things is this kind of like the force that is felt by a burst of photons falling on an object.

zapper you didint' read my whole post?
 
Since "pressure" implies a "change in momentum", this clearly shows that even the classical version of light also contains a description of light having a momentum.

change in momentum with respect to what..

force is with respect to time right? so is pressure the change in momentum with respect to position or what.
 
woodysooner said:
zapper you didint' read my whole post?

I did! You equate "radiation pressure" with photons, which isn't part of the classical picture. Thus, you stated that the classical idea contains no concept of momentum of light, since light has no mass. I disagreed with this by pointing out that with JUST using classical E&M, you can still show that light has a momentum without having to invoke modern physics into it.

Zz.
 
  • #10
ok I'm sorry, your right

By no means am I qualified in any of this stuff just trying to learn
 
  • #11
This came about even with a purely classical treatment of light (i.e. not as photons)

what was it then?? just light, did they not know of photons, and is what is radiation pressure caused from if not by photons, i thought it would be the change in the momentum of photons with respect to position.
 
  • #12
woodysooner said:
change in momentum with respect to what..

force is with respect to time right? so is pressure the change in momentum with respect to position or what.

Er... you do know that F = dp/dt, ya? Furthermore, "pressure" is also proportional to this rate of change of momentum. When light impinges on a surface, if it is either absorbed, or reflected, it has undergone a change in momentum (simple classical mechanics). That is the "change in momentum" that I talked about.

Zz.
 
  • #13
Im sorry zapperz,, really i don't want to upset you, let me look around and learn some more before I ask questions, k, so no one gets frusterated, thanks though.
 
  • #14
woodysooner said:
what was it then?? just light, did they not know of photons, and is what is radiation pressure caused from if not by photons, i thought it would be the change in the momentum of photons with respect to position.

The treatment isn't trivial to describe on here if you haven't had basic E&M. Suffice to say that the E-field vector in light plays a significant role in generating a momentum effect when it impinges upon a surface. That is why this momentum transfer (from light to a surface) is most efficient when the surface is metallic (which is why most solar sails in Sci-Fi books are made of mylar). A metallic surface has "free" conduction electrons, and these electrons are the most easily effected by the oscillating E-field that's present in EM radiation. This interaction between the oscillating E-field in the EM radiation and the surface electrons imparts a "recoil" effect onto the surface. This is what produces the apparent momentum in the classical picture of light, without having to invoke any photon picture.

Zz.
 
  • #15
The sad thing is I have had basic EM
 
  • #16
btw very good definition I see now.
 

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