Objects and stationary observers

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SUMMARY

The discussion centers on the relativistic effects of an object moving at velocities approaching the speed of light, specifically regarding how its dimensions are perceived by a stationary observer. As the object's velocity (v) approaches the speed of light (c), its length contracts according to the formula Lseen by observer = Loriginal * sqrt(1 - (v²/c²)). The width remains unchanged, while the length appears to decrease, confirming that only the dimension parallel to the direction of motion is affected by relativistic effects.

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Dx
Hiya!

An object moves in a direction parallel to its length with a velocity that approaches the velocity of light. The width and length of this object, as measured by a stationary observer is what?

Can anyone gimme more insight on this problem. I am having difficulties understanding just what the hell they are talking about.
does the width approach zero while the length approaches infinity.
Dx [zz)]
 
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Only the dimension in which motion is will change, that is length.
It will get smaller by the factor Sqrt(1-(v2/c2)).
So :
Lseen by observer=Loriginal*sqrt(1-(v2/c2))

Of course, if you wait for an expert to confirm this it would be better.
 
Ok! Just to make sure I am on the right track then. The width does not change but the length approaches zero because a length of an object is measured to be shorter when its moving relative to the observer than at rest.

Yeah? I think I finally got it.

Dx :wink:
 

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