A hideous Linear Regression/confidence set question


by Phillips101
Tags: hideous, linear
Phillips101
Phillips101 is offline
#1
Apr1-10, 08:21 AM
P: 33
Take the linear model Y=X*beta+e, where e~Nn(0, sigma^2 * I), and it has MLE beta.hat

First, find the distribution of (beta.hat-beta)' * X'*X * (beta.hat-beta), where t' is t transpose. I think I've done this. I think it's a sigma^2 chi-squared (n-p) distribution.

Next, Hence find a (1-a)-level confidence set for beta based on a root with an F distribution. I can't do this to save my life. I'm aware that an F distribution is the ratio of two chi-squareds, but where the hell I'm going to get another chi squared from I have no idea. Also, we're dealing in -vectors- and I don't know how,what,why any confidence set is going to be or even look like, and I've no idea how to even try to get one.

-Any- help would be appreciated. Thanks
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statdad
statdad is offline
#2
Apr2-10, 07:08 PM
HW Helper
P: 1,344
Notice that

[tex]
\frac{\hat{\beta}' X'X \hat{\beta}}{\sigma^2}
[/tex]

has a [tex] \Chi^2 [/tex] distribution. however, the variance is unknown, so you need to estimate it (with another expression from the regression). What would you use for the estimate, and what is its distribution?
Phillips101
Phillips101 is offline
#3
Apr3-10, 05:43 AM
P: 33
Use the MLE sigma2.hat=(1/n)*||Y-Xbeta.hat||^2 ? This is distributed as a chi-squared n-1 variable if I remember correctly...

Phillips101
Phillips101 is offline
#4
Apr3-10, 05:45 AM
P: 33

A hideous Linear Regression/confidence set question


If that's correct, then the thing you posted is distributed as an F distribution, which is what I need? And would swapping beta.hat for beta.hat-beta make any difference to this?


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