Solving Distributed Load Homework: Reaction Forces at A and B

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SUMMARY

The discussion focuses on calculating the reaction forces at points A and B in a distributed load scenario. The user initially calculated the reaction force at B as 1.5kN using incorrect moment calculations. The correct approach involves using the area of the load (1.8kN) and applying the moment equation correctly, resulting in a reaction force at B of 0.45kN. The user also inquired about the meaning of a dot at point A, indicating a need for clarification on notation in structural analysis.

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  • Understanding of static equilibrium principles
  • Familiarity with calculating moments in mechanics
  • Knowledge of distributed load concepts
  • Basic skills in structural analysis notation
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  • Review the principles of static equilibrium in mechanics
  • Learn about calculating moments with distributed loads
  • Study structural analysis notation and symbols
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Students in engineering or physics courses, particularly those studying mechanics and structural analysis, as well as educators looking for examples of distributed load calculations.

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Homework Statement


To find the reaction at A and B. (See image below)
DistributedLoad.jpg



Homework Equations


Moments and Area


The Attempt at a Solution


Area of load: (0.3)(6) = 1.8kN
Moments about A: -(6)(0.15) + RB(0.6) = 0 --> RB = 1.5kN


4. The error and question
I get the reaction force at B to be 1.5kN but the answer states that it is 0.45kN. What am I doing wrong?
 
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"-(6)(0.15) " is wrong.
 
Oh yes. It's -(1.8)(0.5). Found 1.8 in the step earlier and forgot to put that in. Thanks.
 
Also, what is that dot they have in the bar mean? At point A.
 

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