Solving Distributed Load Homework: Reaction Forces at A and B

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The discussion focuses on calculating the reaction forces at points A and B in a distributed load problem. The initial calculation for the reaction force at B was incorrectly derived as 1.5kN due to a mistake in the moment equation. The correct approach involves using the total load of 1.8kN and adjusting the moment calculation to reflect this. The correct reaction force at B is identified as 0.45kN after correcting the moment equation. Additionally, there is a query regarding the meaning of a dot notation at point A, indicating a need for clarification on notation used in structural analysis.
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Homework Statement


To find the reaction at A and B. (See image below)
DistributedLoad.jpg



Homework Equations


Moments and Area


The Attempt at a Solution


Area of load: (0.3)(6) = 1.8kN
Moments about A: -(6)(0.15) + RB(0.6) = 0 --> RB = 1.5kN


4. The error and question
I get the reaction force at B to be 1.5kN but the answer states that it is 0.45kN. What am I doing wrong?
 
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"-(6)(0.15) " is wrong.
 
Oh yes. It's -(1.8)(0.5). Found 1.8 in the step earlier and forgot to put that in. Thanks.
 
Also, what is that dot they have in the bar mean? At point A.
 
So is there some elegant way to do this or am I just supposed to follow my nose and sub the Taylor expansions for terms in the two boost matrices under the assumption ##v,w\ll 1##, then do three ugly matrix multiplications and get some horrifying kludge for ##R## and show that the product of ##R## and its transpose is the identity matrix with det(R)=1? Without loss of generality I made ##\mathbf{v}## point along the x-axis and since ##\mathbf{v}\cdot\mathbf{w} = 0## I set ##w_1 = 0## to...

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