Maximum velocity of a piston

1. The problem statement, all variables and given/known data
A piston in an automobile engine is in simple harmonic motion. Its amplitude of oscillation from the equilibrium (centered) position is ±4.73 cm and its mass is 1.733 kg. Find the maximum velocity of the piston when the auto engine is running at the rate of 4380 rev/min.

2. Relevant equations

Vmax=Aw

3. The attempt at a solution
I attempted to take the Amplitude (.0437 m) and multiply it by the angular frequency. I first converted it into revolutions per second and then divided 2pi by the answer I got.
 Recognitions: Gold Member Hello Bearbull,w=2pif.
 And f=1/T and T=4380 rev/min= 73 rev/s?

Maximum velocity of a piston

Got it wrong again,

Vmax=(.0437m)(2pi(1/73rev/s))
 Recognitions: Gold Member f=4380r/min=4380/60 revs/second=73r/s

 Quote by Bearbull24.5 And f=1/T and T=4380 rev/min= 73 rev/s?
This part is wrong. Remember 1 rev = 2pi.
So you multiply by 2pi, and then 1 min = 60 seconds. So you divide by 60 seconds. I did not get 73 rev/s. I got another number.
 Recognitions: Gold Member w=2pitimes73
 I did 2pi*73 rev/s and then multiplied it by my amplitude (.0437 m). Got it wrong.

Recognitions:
Gold Member
 Quote by Bearbull24.5 I did 2pi*73 rev/s and then multiplied it by my amplitude (.0437 m). Got it wrong.