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Function, using two-path test, finding limits |
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| Apr29-10, 09:29 PM | #1 |
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Function, using two-path test, finding limits
f(x,y)=(x)/ (1-y2), y does not equal 1 or -1
Is it possible to define a new function g(x,y) that is defined and continuous for all (x,y) in R2, and such that g(x,y)=f(x,y) for all (x,y) in the domain of f? If so, find such a function. If not, explain why. I really don't know where to begin... 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
| May1-10, 03:02 PM | #2 |
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For the existence of such g it is necesarry that lim (x->x0, y->1) f(x,y)=A(x0,1) exist and depend only on x0 (and not on the path). But in our case it does not hold:
Calculate the limit for x0=0 for two different paths: 1. y=x+1 (x->0) 2. y=2x+1 (x->0) You wont get the same result, so such g does NOT exist. |
| Apr18-12, 02:05 PM | #3 |
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how do i choose the equations of lines c and d,to find limits along when finding limits by two parts
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